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MA_775_DIABLO [31]
3 years ago
12

24 students in Jamal's class are wearing tennis shoes. There are 30 students in his class. Jamal says that 70% of his class is w

earing tennis shoes. Is Jamal correct
Mathematics
1 answer:
allsm [11]3 years ago
7 0
No 70 percent is 21 students
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4+ -1 2/3 please help
kogti [31]

The sum would end us as: 2.33333333

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3 years ago
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Determine whether Point A lies on the circle whose center is Point C and whichcontains the Point P. Justify your answer mathemat
Arada [10]

The Solution:

Given:

Center = (0,0)

Point A = (-5,2) being a point on the circle.

We are required to check if point P = (2,-5) is on the circle.

Solving the given problem graphically, we have:

From the above graph, it is clear that point P(2,-5) is a point on the circle.

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1 year ago
What is the slope of line a?<br><br> • -4<br> • 4<br> • -1/4<br> • 1/4
Shtirlitz [24]
I think it’s four. If not then I’m sorry
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3 years ago
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Stan's Sweater Superstore has a 30% off sale. This week only, everything in the store is marked down an additional 10% off the s
evablogger [386]

Answer:

$30

Step-by-step explanation:

30 % + 10 % = 40 %

40 % of $50 = $20

%50 - $20 = $30

8 0
3 years ago
Allied Corporation is trying to sell its new machines to Ajax. Allied claims that the machine will pay for itself since the time
kvasek [131]

Answer:

z(s) is in the acceptance region. We accept H₀  we did not find a significantly difference in the performance of the two machines therefore we suggest not to buy a new machine

Step-by-step explanation:

We must evaluate the differences of the means of the two machines, to do so, we will assume a CI  of 95%, and as the interest is to find out if the new machine has better performance ( machine has a bigger efficiency or the new machine produces more units per unit of time than the old one) the test will be a one tail-test (to the left).

New machine

Sample mean                  x₁ =    25

Sample variance               s₁  = 27

Sample size                       n₁  = 45

Old machine

Sample mean                    x₂ =  23  

Sample variance               s₂  = 7,56

Sample size                       n₂  = 36

Test Hypothesis:

Null hypothesis                         H₀             x₂  -  x₁  = d = 0

Alternative hypothesis             Hₐ            x₂  -  x₁  <  0

CI = 90 %  ⇒  α =  10 %     α = 0,1      z(c) = - 1,28

To calculate z(s)

z(s)  =  ( x₂  -  x₁ ) / √s₁² / n₁  +  s₂² / n₂

s₁  = 27     ⇒    s₁²  =  729

n₁  = 45    ⇒   s₁² / n₁    = 16,2

s₂  = 7,56   ⇒    s₂²  = 57,15

n₂  = 36     ⇒    s₂² / n₂  =  1,5876

√s₁² / n₁  +  s₂² / n₂  =  √ 16,2  + 1.5876    = 4,2175

z(s) = (23 - 25 )/4,2175

z(s)  =  - 0,4742

Comparing z(s) and  z(c)

|z(s)| < | z(c)|  

z(s) is in the acceptance region. We accept H₀  we did not find a significantly difference in the performance of the two machines therefore we suggest not to buy a new machine

The very hight dispersion of values s₁ = 27 is evidence of frecuent values quite far from the mean

3 0
3 years ago
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