Answer:
A( multiply both sides by 6)
As seen , the L.C.M is 6 so to do away with the fractional form, we will multiply by 6
Answer:
The requirements that are necessary for a normal probability distribution to be a standard normal probability distribution are <em>µ</em> = 0 and <em>σ</em> = 1.
Step-by-step explanation:
A normal-distribution is an accurate symmetric-distribution of experimental data-values.
If we create a histogram on data-values that are normally distributed, the figure of columns form a symmetrical bell shape.
If X
N (µ, σ²), then
, is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z
N (0, 1).
The distribution of these z-variates is known as the standard normal distribution.
Thus, the requirements that are necessary for a normal probability distribution to be a standard normal probability distribution are <em>µ</em> = 0 and <em>σ</em> = 1.
Answer:
I think it would be -4x-6y+12
Answer: i believe you're trying to find N, if so N=3
Step-by-step explanation:
you would start by adding +2 to each side of the equation, leaving you with 3n=9
you would then divide each side by 3, which gives you N=3