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hjlf
4 years ago
13

83,023,007 in expanded form

Mathematics
1 answer:
anyanavicka [17]4 years ago
7 0
80000000+20000+3000+7
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3 x+1<br> ------- + ---------------<br> 92−64 152−7−40
RSB [31]

Answer:

1

Step-by-step explanation:

\frac{3x + 1}{28}  +  \frac{}{105}  \\  \frac{105(3x + 1)}{2940}  +  \frac{28}{2940}  \\  \frac{3x + 1}{28}  +  \frac{1}{105}

4 0
3 years ago
What is the value of x?
Rama09 [41]

Answer:

x = 70

Step-by-step explanation:

45+2x-5 = 180

2x = 180 - 40

x = 140/2

x = 70

5 0
3 years ago
What is the population in 2020 of a place that has a population of 4 million people in 2011 and is growing at a rate of 1.3%?
Stolb23 [73]

Answer:

370 million

Step-by-step explanation:

In the 10 years from 2000 to 2010, the population was multiplied by the factor ...

100% + 9.6% = 109.6% = 1.096

In the next 20 years from 2010 to 2030, the population will be multiplied by that factor twice, if it grows at the same rate:

2030 population = (308 million)·(1.096²) ≈ 370 million

5 0
3 years ago
What is the answer for -2x = 34
Hunter-Best [27]
To solve:

-2x = 34
----- -----
-2 -2

(-2x means -2 times x, so to undo this we need to divide by -2 on both sides)

x = -17

Then you do basic division (knowing that a positive divided by a negative results in a negative answer). And that's it!
7 0
3 years ago
Read 2 more answers
The nth term of a sequence is 3n2-1
maksim [4K]

Answer: The common number is 26.

Step-by-step explanation:

We know that the n-th term of a sequence is:

aₙ = 3*n^2 - 1

And the n-th term of another sequence is:

bₙ = 30 - n^2

Remember that in a sequence n is always an integer number.

We want to find a number that belongs to both sequences, then we want to find a pair of integers x and n, such that:

aₙ = bₓ

This is:

3*n^2 - 1 = 30 - x^2

Let's isolate one of the variables, i will isolate n.

3*n^2 = 30 - x^2 + 1 = 31 - x^2

n^2 = (31 - x^2)/3

n = √( (31 - x^2)/3)

Now we can try with different integer values of x, and see if n is also an integer.

if x = 1

n = √( (31 - 1^2)/3) = √10

We know that √10 is not an integer, so we need to try with another value of x.

if x = 2:

n = √( (31 - x^2)/3) = √(27/3) = √9 = 3

Then if we have x= 2, n is also an integer, n = 3.

Then we have:

a₃ = b₂

The common number between both sequences is:

a₃ = 3*(3)^2 - 1 = 26

b₂ = 30 - 2^2 = 26

6 0
4 years ago
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