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storchak [24]
3 years ago
11

Describe how to find the area of a parallelogram. Explain why.

Mathematics
2 answers:
S_A_V [24]3 years ago
8 0
A=bh {A} stands for the area, {b} stands for the length of your parallelogram, and {h} stands for the height of your parallelogram.
Vanyuwa [196]3 years ago
4 0
It is the exact same as a rectangle (bxh) because if you imagine moving the right triangle on one side to the other side (putting the two hypotenuses of the triangles together), you create a rectangle which the formula for area is A=bxh

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Parallelogram ABCD has the angle measures shown. Can you conclude that it is a rhombus, a rectangle, or a square? Explain.
Hoochie [10]

Answer:

The correct option is parallelogram ABCD is a rhombus, because the diagonal bisects two angles

Step-by-step explanation:

In triangle ABD:

∠B = ∠D

Thus AB=AC by the property of opposite sides of equal angles are equal

In triangle CBD

∠B = ∠D

Thus CB=CD  by the property of opposite sides of equal angles are equal

Thus all four sides of quadrilateral ABCD are equal  

And diagonal BD bisects the angles  

So, it is a rhombus

Therefore the correct option is  parallelogram ABCD is a rhombus, because the diagonal bisects two angles....

5 0
3 years ago
Which property of multiplication is shown below?
Lubov Fominskaja [6]
There are four properties of multiplication namely commutative, associative, multiplicative identity and distributive. The equation given defines the commutative property of multiplication where two numbers are multiplied, the product will still be the same no matter what is the order of the multiplicands.
3 0
3 years ago
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A King in ancient times agreed to reward the inventor of chess with one grain of wheat on the first of the 64 squares of a chess
statuscvo [17]
Let's start by visualising this concept.

Number of grains on square:
1   2   4   8   16 ...

We can see that it starts to form a geometric sequence, with the common ratio being 2.

For the first question, we simply want the fifteenth term, so we just use the nth term geometric form:
T_n = ar^{n - 1}
T_{15} = 2^{14} = 16384

Thus, there are 16, 384 grains on the fifteenth square.

The second question begs the same process, only this time, it's a summation. Using our sum to n terms of geometric sequence, we get:
S_n = \frac{a(r^{n} - 1)}{r - 1}
S_{15} = \frac{2^{15} - 1}{2 - 1}
S_{15} = 2^{15} - 1 = 32767

Thus, there are 32, 767 total grains on the first 15 squares, and you should be able to work the rest from here.
6 0
3 years ago
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PLSSSS HELP ME NOWW I DONT GET IT
kari74 [83]

Answer:

B

Step-by-step explanation:

8 0
3 years ago
6h+(-7.3d)-13+5d-2.6h=? PLEASE HELP ASAP​
Strike441 [17]

Answer:

-2.3d+3.4h-13

Step-by-step explanation:

4 0
3 years ago
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