Answer: A pure mathematics internet could be a 2-dimensional form that may be rolled-up to make a three-d form or a solid. Or a internet could be a pattern created once the surface of a solid figure is ordered out flat showing every face of the figure. A solid could have totally different nets.
Step-by-step explanation: A pure mathematics web could be a 2-dimensional form which will be closed to make a third-dimensional form or a solid. Or a web could be a pattern created once the surface of a solid figure is arranged out flat showing every face of the figure. A solid could have completely different nets.
Answer: 3.49
Step-by-step explanation:
When standard deviation is known then the test statistic for difference of two population means (independent population) is given by :-
![z=\dfrac{\overline{X}-\overline{Y}}{\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}}](https://tex.z-dn.net/?f=z%3D%5Cdfrac%7B%5Coverline%7BX%7D-%5Coverline%7BY%7D%7D%7B%5Csqrt%7B%5Cdfrac%7B%5Csigma_1%5E2%7D%7Bn_1%7D%2B%5Cdfrac%7B%5Csigma_2%5E2%7D%7Bn_2%7D%7D%7D)
Given : ![n_1=86\ \ , \ n_2=113](https://tex.z-dn.net/?f=n_1%3D86%5C%20%5C%20%2C%20%5C%20n_2%3D113)
![\overline{X}=45.67\ \ , \ \overline{Y}=39.87](https://tex.z-dn.net/?f=%5Coverline%7BX%7D%3D45.67%5C%20%5C%20%2C%20%5C%20%5Coverline%7BY%7D%3D39.87)
![\sigma_1=10.90\ \ ,\ \sigma_2=12.47](https://tex.z-dn.net/?f=%5Csigma_1%3D10.90%5C%20%5C%20%2C%5C%20%5Csigma_2%3D12.47)
Then , the value of the test statistic will be :-
![z=\dfrac{45.67-39.87}{\sqrt{\dfrac{(10.9)^2}{86}+\dfrac{(12.47)^2}{113}}}\\\\=\dfrac{5.8}{\sqrt{2.757625787}}=3.4926923081\approx3.49](https://tex.z-dn.net/?f=z%3D%5Cdfrac%7B45.67-39.87%7D%7B%5Csqrt%7B%5Cdfrac%7B%2810.9%29%5E2%7D%7B86%7D%2B%5Cdfrac%7B%2812.47%29%5E2%7D%7B113%7D%7D%7D%5C%5C%5C%5C%3D%5Cdfrac%7B5.8%7D%7B%5Csqrt%7B2.757625787%7D%7D%3D3.4926923081%5Capprox3.49)
Hence, the value of the test statistic = 3.49
The two plans cost the same at 450miles.
The cost is $118.50 when the two plans cost the same.
Working is in the photo.
Answer:
a) 95% of the widget weights lie between 29 and 57 ounces.
b) What percentage of the widget weights lie between 12 and 57 ounces? about 97.5%
c) What percentage of the widget weights lie above 30? about 97.5%
Step-by-step explanation:
The empirical rule for a mean of 43 and a standard deviation of 7 is shown below.
a) 29 represents two standard deviations below the mean, and 57 represents two standard deviations above the mean, so, 95% of the widget weights lie between 29 and 57 ounces.
b) 22 represents three standard deviations below the mean, and the percentage of the widget weights below 22 is only 0.15%. We can say that the percentage of widget weights below 12 is about 0. Equivalently we can say that the percentage of widget weights between 12 an 43 is about 50% and the percentage of widget weights between 43 and 57 is 47.5%. Therefore, the percentage of the widget weights that lie between 12 and 57 ounces is about 97.5%
c) The percentage of widget weights that lie above 29 is 47.5% + 50% = 97.5%. We can consider that the percentage of the widget weights that lie above 30 is about 97.5%