Question

A plumber and his assistant work together to replace the pipes in an old house. The plumber charges $30 an hour for his own labor and $15 an hour for his assistant's labor. The plumber works twice as long as his assistant on this job, and the labor charge on the final bill is $1875. How long did the plumber and his assistant work on this job?

Answer 1

Answer:

hours of work done by assistant = 17.85

hours of work done by plumber  = 35.7

Explanation:

Given data:

charges of plumber is $30

charges of assitant is $15

total labor charge is $1875

let x  is the total hour of job by assistant  

and 2x is total hours of job by plumber

so we have

15x + 30\times 2x = 1875

15x + 90x = 1875

105x = 1875

x =  17.85

therefore plumber work 2x i.e 35.7

hours of work done by assistant = 17.85

hours of work done by plumber  = 35.7