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3 years ago

Lim 9x^2/x+2 when x is infinity

Mathematics

1 answer:

lara31 [8.8K]3 years ago

7 0

Answer:

Step-by-step explanation:

$\lim_{x \to +\infty}\frac{9x^{2} }{x+2} = \lim_{x \to +\infty}\frac{9x^{2} }{x}= \lim_{x \to +\infty}9x = +\infty\\\\ \lim_{x \to -\infty}\frac{9x^{2} }{x+2} = \lim_{x \to -\infty}\frac{9x^{2} }{x}= \lim_{x \to -\infty}9x = -\infty\\$

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creativ13 [48]

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3 years ago

The amount that households pay service providers for access to the Internet varies quite a bit, but the mean monthly fee is $50

Natali5045456 [20]

Answer:

(a) See Explanation

(b) $\bar x =50$ and $\sigma_x = 0.8944$

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Step-by-step explanation:

Given

$\mu = \$50$ -- mean

$\sigma = \$20$ --- standard deviation

$n=500$ --- sample size

Solving (a): The reason we can't determine the probability that an amount to access internet by a household will exceed $55.

The question says that a lot of households pay low rates, but the percentage of the households in this category is not given. This means that it is impossible to determine the shape of the distribution.

Hence, the probability cannot be calculated.

Solving (b): Sample mean and Sample standard deviation

The sample mean estimates the population mean

So:

$\bar x =\mu$

$\bar x =50$

The sample standard deviation is calculated as thus:

$\sigma_x = \frac{\sigma}{\sqrt n}$

$\sigma_x = \frac{20}{\sqrt{500}}$

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Solving (c): The shape of the distribution.

We have:

$n = 500$ --- The sample size

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<em>Hence, the shape is normal</em>

Solving (d): $P(\bar x \ge 55)$

Calculate the test statistic (t)

$t = \frac{\bar x - \mu}{\sigma}$

$t = \frac{55 - 50}{0.8945}$

$t = \frac{5}{0.8945}$

$t = 5.590$

So:

$P(\bar x > 55) = P(t > 5.590)$

Referencing the z table, we have:

$P(t > 5.590) = 0$

Hence:

$P(\bar x > 55) = 0$

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3 years ago

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3 years ago

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3 years ago

Lim 9x^2/x+2 when x is infinity​

Lim 9x^2/x+2 when x is infinity