<u>Solution-</u>
Given that,
In the parallelogram PQRS has PQ=RS=8 cm and diagonal QS= 10 cm.
Then considering ΔPQT and ΔSTF,
1- ∠FTS ≅ ∠PTQ ( ∵ These two are vertical angles)
2- ∠TFS ≅ ∠TPQ ( ∵ These two are alternate interior angles)
3- ∠TSF ≅ ∠TQP ( ∵ These two are also alternate interior angles)
<em>If the corresponding angles of two triangles are congruent, then they are said to be similar and the corresponding sides are in proportion.</em>
∴ ΔFTS ∼ ΔPTQ, so corresponding side lengths are in proportion.

As QS = TQ + TS = 10 (given)
If TS is x, then TQ will be 10-x. Then putting these values in the equation



∴ So TS = 3.85 cm and TQ is 10-3.85 = 6.15 cm
Coefficient is 6 and -5
constant is xy
Answer:
C??????????????? ?????????
Answer:
Formulate
Based on the given conditions, formulate:

Evaluate
Evaluate the equation/expression:
20.78461
SO THE ANSWER IS 20.78461
the answer is
<span>[√8k ]² =k²,
so 8k=k² which implies k² - 8k= 0, and (k
– 8)k= 0, so k = 8 or k =0</span>