Answer: a)
<u>Step-by-step explanation:</u>
Matrix multiplication is the sum of Row 1 (of first matrix) x Column 1 (of second matrix) ...repeat for each row.
Transpose means to switch the rows to columns.
![A=\left[\begin{array}{cc}5&2\\3&-1\end{array}\right] \qquad \times \qquad A^T=\left[\begin{array}{cc}5&3\\2&-1\end{array}\right] \\\\\\= \left[\begin{array}{cc}5(5)+2(2)&5(3)+2(-1)\\3(5)+(-1)(2)&3(3)+(-1)(-1)\end{array}\right] \\\\\\= \left[\begin{array}{cc}29&13\\13&10\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D5%262%5C%5C3%26-1%5Cend%7Barray%7D%5Cright%5D%20%5Cqquad%20%5Ctimes%20%5Cqquad%20A%5ET%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D5%263%5C%5C2%26-1%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%5C%5C%5C%5C%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D5%285%29%2B2%282%29%265%283%29%2B2%28-1%29%5C%5C3%285%29%2B%28-1%29%282%29%263%283%29%2B%28-1%29%28-1%29%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%5C%5C%5C%5C%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D29%2613%5C%5C13%2610%5Cend%7Barray%7D%5Cright%5D)
Answer:
the 1st answer is H, yw
Step-by-step explanation:
quadrant I is on the top right, quadrant II is on the upper left, quadrant III is on the bottom left, and quadrant IV is on the bottom right. H is located in the top left (quadrant 2)
Answer:
<h2>H = 60° </h2>
Step-by-step explanation:
To find angle H we use tan
tan ∅ = opposite / adjacent
From the question
The opposite is 2√21
The adjacent is 2√7
So that's
tan H = 2√21/ 2√7
H= tan-¹ 2√21/ 2√7
<h3>H = 60° </h3>
Hope this helps you
Answer:
.0075 (hope this help; let me know if not)
Step-by-step explanation:
The operation is + and the signs of the numbers are opposite so we have to subtract. The bigger number has positive sign in front if so we do 1.2-1.125=1.200-1.125
I'm going to line up
1.200
-1.125
---------
If you have 200 and you take about 125... 75 should beleft
so
1.200
-1.125
---------
0.075
ANSWER
![\frac{1}{2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B2%7D%20)
EXPLANATION
The frequency of a wave function refers to the number of times the graph repeats its cycle within the interval [0,2π]
We can observe explicitly from the graph that the frequency is half.
The period of the given function is 4π
![\frac{2\pi}{b} = 4\pi](https://tex.z-dn.net/?f=%20%5Cfrac%7B2%5Cpi%7D%7Bb%7D%20%3D%204%5Cpi)
![b = \frac{2\pi}{4\pi} = \frac{1}{2}](https://tex.z-dn.net/?f=b%20%3D%20%20%5Cfrac%7B2%5Cpi%7D%7B4%5Cpi%7D%20%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20)
Hence the frequency is half.