Part A
t 0 1 2 3
H(t) 12 44 44 42
g(t) 10 25 40 56
Set H(t) = g(t) yields 16t^2 -32t -2 which shows its zeroes or points of intersections are at 0.6 and 2.1 seconds
Part B
H(t) = g(t) intersect at (x,y) points (0.6 secs, 9.1 feet) and (2.1 secs, 42.1 feet)
H(t) is a parabola that opens downward which shows the cannonball arches upwards then falls downward.
g(t) is a straight linear line which slopes positive upwards and intersects G(t) in two places.
Its you will be found and the equation answer is 56
<u>Answer:</u>
(-1, 5)
<u>Step-by-step explanation:</u>
The center of a circle is the midpoint of the diameter.
So we have to calculate the midpoint of the diameter, using this formula:
midpoint = (
,
)
= (
,
)
= (-1, 5)
∴ The center of the circle lies at the point (-1, 5).
Answer:
10
Step-by-step explanation:
Use PEMDAS to rewrite the equation as:
m - (2 * n) + 2 =
16 - (2 * 4) + 2 =
16 - 8 + 2 =
10
The 9 is a coefficient because it is the first one before an 'algebraic number'. :)