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Greeley [361]
3 years ago
10

Must a function that is decreasing over a given interval always be negative over that same interval ? Explain

Mathematics
2 answers:
lyudmila [28]3 years ago
8 0

Answer:

For a function to be decreasing over an interval, the outputs on the function are getting smaller as the inputs of the function are getting larger, but the outputs could be positive or negative. For a function to be negative over an interval, the  outputs must be negative, while the inputs could be positive or negative.

Leno4ka [110]3 years ago
5 0
Check the picture below.

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A car drives at a rate of 65 mi/hr. what is the speed of the car in ft/s? note: 1 mi = 5280 ft
lana66690 [7]

Answer:. 95.33 ft/sec

Multiply 65 by 5280 to get 343200 feet per hour. Then Divide by 3600. There are 60 minutes in an hour, and 60 seconds in a minute.

343200 ÷ 3600 = 95.333

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Please help & thank you.
MA_775_DIABLO [31]

Answer:

<em>9</em>

Step-by-step explanation:

2(5y°) = 90° ⇒ y = <em>9</em>

3 0
3 years ago
What's the lower bound of 3.05​
Verizon [17]

Answer:

I think its 20.....

Step-by-step explanation:

Plz don't be mad if I'm wrong..... lol :/

4 0
3 years ago
The table gives estimates of the world population, in millions, from 1750 to 2000. year population year population 1750 790 1900
Tems11 [23]
The poopulation exponential model is given by

P(t)=P_0e^{kt}

Where, P(t) is the population after year t; Po is the initial population, t is the number of years from the starting year; k is the groth constant.

Given that the population in 1750 is 790 and the population in 1800 is 970, we obtain the population exponential equation as follows:

970=790e^{50k} \\  \\ \Rightarrow e^{50k}=1.228 \\  \\ \Rightarrow 50k=\ln{1.228}=0.2053 \\  \\ \Rightarrow k=0.0041

Thus, the exponential equation using the 1750 and the 1800 population values is P(t)=790e^{0.0041t}

The population of 1900 using the 1750 and the 1800 population values is given by

P(t)=790e^{0.041\times150} \\  \\ =790e^{0.6158}=790(1.8511) \\  \\ =1,462

The population of 1950 using the 1750 and the 1800 population values is given by

P(t)=790e^{0.041\times200} \\  \\ =790e^{0.821}=790(2.2729) \\  \\ =1,796

From the table, it can be seen that the actual figure is greater than the exponential model values.
7 0
3 years ago
I really just need help with part C, Also this is 50 points!
ziro4ka [17]
2.418 x 10^8 is the answer.
6 0
3 years ago
Read 2 more answers
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