The taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16 
/2!+...........
Given a function f(x)=9/x,a=-4.
We are required to find the taylor series for the function f(x)=8/x centered at the given value of a and a=-4.
The taylor series of a function f(x)=
Where the terms in f prime 
(a) represent the derivatives of x valued at a.
For the given function.f(x)=8/x and a=-4.
So,f(a)=f(-4)=8/(-4)=-2.
(a)=(-4)=-8/(
=-8/16
=-1/2
The series of f(x) is as under:
f(x)=f(-4)+
=-2+2(x+4)/1!-24/16 /2!+...........
Hence the taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16 /2!+...........
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The answer to your question is x= -12 hope this helps ! Makes sure you put the negative !
Mark brainliest please mark
Answer:
(9.37, 17.7) ; (14.10, 19.42); (20.8, 22.3)
Step-by-step explanation:
For the first picture :
The missing angle :
180 - (32 + 90)
180 - (122) = 58°
To obtain the length of side x:
From ptthagoras:
Tan58° = opposite / Adjacent
1.6003345 = 15 / x
x = 15 / 1.6003345
= 9.37
y = sqrt(15^2 + 9.37^2)
y = sqrt(312.7969)
y = 17.7m
2)
Missing angle :
From ptthagoras :
Sin54° = opposite / hypotenus
0.8090169 = y/ 24
y = 0.8090169 * 24
y = 19.42
x = sqrt(24^2 - 19.42^2)
x = sqrt(198.8636)
x = 14.10
3)
Sin21° = opposite / hypotenus
0.3583679 = 8 /y
y = 8 / 0.3583679
y = 22.3
x = sqrt(22.3^2 - 8^2)
x = sqrt(433.29)
x = 20.8
