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Salsk061 [2.6K]
3 years ago
10

Solve the system of linear equations by substitution x+4y =37 y = -x + 16

Mathematics
1 answer:
pantera1 [17]3 years ago
4 0
You plug -x+16 in for y in x+4y=37 to get x after you multiply x+4y=37 by -1.
-x-4(-x+16)=-37
-x+4x-64=-37
3x-64=-37
3x=27
x=9
Then you plug 9 into either equation to get y.
y=-x+16
y=-(9)+16
y=7

x=9 and y=7
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Find the taylor series for f(x) centered at the given value of a. [assume that f has a power series expansion. do not show that
RUDIKE [14]

The taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16 (x+4)^{2}/2!+...........

Given a function f(x)=9/x,a=-4.

We are required to find the taylor series for the function f(x)=8/x centered at the given value of a and a=-4.

The taylor series of a function f(x)=f(a)+f^{1}(a)(x-a)/1!+ f^{11}(a)(x-a)^{2} /2! +f^{111}(a)(x-a)a^{3}/3!+..........

Where the terms in f prime f^{1}(a) represent the derivatives of x valued at a.

For the given function.f(x)=8/x and a=-4.

So,f(a)=f(-4)=8/(-4)=-2.

f^{1}(a)=f^{1}(-4)=-8/(-4)^{2}

=-8/16

=-1/2

The series of f(x) is as under:

f(x)=f(-4)+f^{1}(-4)(x+4)/1!+  f^{11}(-4)(x+4)^{2}/2!.............

=8/(-4)-8/(-4)^{2} (-4)(x+4)/1!+  24/(-4)^{3} (-4)(x+4)^{2}/2!.............

=-2+2(x+4)/1!-24/16 (x+4)^{2}/2!+...........

Hence the taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16 (x+4)^{2}/2!+...........

Learn more about taylor series at brainly.com/question/23334489

#SPJ4

3 0
1 year ago
Solve for x.<br><br> -98=4x-50
alexdok [17]
The answer to your question is x= -12 hope this helps ! Makes sure you put the negative !
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3 years ago
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sweet-ann [11.9K]
Mark brainliest please mark

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The sum of three consecutive odd integers is 17 less than four times the smallest integer
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4 0
3 years ago
PLEASE HELP!!!!!!!Find the length of the missing sides. Round your answers to the nearest tenth. (Hint: Always make sure to labe
Reptile [31]

Answer:

(9.37, 17.7) ; (14.10, 19.42); (20.8, 22.3)

Step-by-step explanation:

For the first picture :

The missing angle :

180 - (32 + 90)

180 - (122) = 58°

To obtain the length of side x:

From ptthagoras:

Tan58° = opposite / Adjacent

1.6003345 = 15 / x

x = 15 / 1.6003345

= 9.37

y = sqrt(15^2 + 9.37^2)

y = sqrt(312.7969)

y = 17.7m

2)

Missing angle :

From ptthagoras :

Sin54° = opposite / hypotenus

0.8090169 = y/ 24

y = 0.8090169 * 24

y = 19.42

x = sqrt(24^2 - 19.42^2)

x = sqrt(198.8636)

x = 14.10

3)

Sin21° = opposite / hypotenus

0.3583679 = 8 /y

y = 8 / 0.3583679

y = 22.3

x = sqrt(22.3^2 - 8^2)

x = sqrt(433.29)

x = 20.8

7 0
3 years ago
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