Answer:
Step-by-step explanation:
It's never negative.
The tan(-x) is the same thing as -tan(x). The tangent function is also the same thing as sin(x)/cos(x), right? So let's rewrite that tan in terms of sin and cos:
![[cos(x)][tan(-x)]](https://tex.z-dn.net/?f=%5Bcos%28x%29%5D%5Btan%28-x%29%5D)
is the same as
![[cos(x)][ -\frac{sin(x)}{cos(x)}]](https://tex.z-dn.net/?f=%5Bcos%28x%29%5D%5B%20-%5Cfrac%7Bsin%28x%29%7D%7Bcos%28x%29%7D%5D%20)
We can now cancel out the cos(x), which leaves us only with -sin(x) remaining. So your answer is A.
The intercepts of the given equations is as given in the task content is; Choice B; (15,0,0),(0,10,0) ,(0,0,5).
<h3>What are the intercepts of the equation as give in the task content?</h3>
The x-intercept of the given equation can be determined by setting values of y and z to zero.
The y-intercept can be determined by setting x and z to zero.
While the z-intercept can be determined by setting x and y to zero.
Consequently, the X-intercept of the given equations is; 2x +3(0) = 30; x = 15.
Therefore, we have; (15,0,0)
The y-intercept is therefore; 2(0) +3y = 30; 3y = 30; y = 30/3 = 10 and. we have; (0,15,0)
And hence, the z-intercept is; z = 30/6 = 5.
Read more on intercept;
brainly.com/question/1884491
#SPJ1
Erica will take 4.5 minutes to run from home to school
<h3><u>Solution:</u></h3>
Given that , Arica can run
of a kilometer in a minute
Her school is
th of a kilometer away from her home
We have to find at this speed how long will it take Erica to run from home to school
<em><u>The relation between speed distance and time is given as:</u></em>
![\text { Distance }=\text { speed } \times \text { time }](https://tex.z-dn.net/?f=%5Ctext%20%7B%20Distance%20%7D%3D%5Ctext%20%7B%20speed%20%7D%20%5Ctimes%20%5Ctext%20%7B%20time%20%7D)
Plugging in values, we get
![\frac{3}{4}=\frac{1}{6} \times \text { time taken }](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B4%7D%3D%5Cfrac%7B1%7D%7B6%7D%20%5Ctimes%20%5Ctext%20%7B%20time%20taken%20%7D)
![\begin{array}{l}{\text { Time taken to reach school }=\frac{3}{4} \times 6} \\\\ {\text { Time taken to reach home }=\frac{3}{2} \times 3} \\\\ {\text { Time taken to reach home }=\frac{9}{2}=4.5}\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bl%7D%7B%5Ctext%20%7B%20Time%20taken%20to%20reach%20school%20%7D%3D%5Cfrac%7B3%7D%7B4%7D%20%5Ctimes%206%7D%20%5C%5C%5C%5C%20%7B%5Ctext%20%7B%20Time%20taken%20to%20reach%20home%20%7D%3D%5Cfrac%7B3%7D%7B2%7D%20%5Ctimes%203%7D%20%5C%5C%5C%5C%20%7B%5Ctext%20%7B%20Time%20taken%20to%20reach%20home%20%7D%3D%5Cfrac%7B9%7D%7B2%7D%3D4.5%7D%5Cend%7Barray%7D)
Hence, she takes 4.5 minutes to reach school from her home