Answer:
B
Step-by-step explanation:
The given equation y = 2x^2 -12x - 32 can be factored as follows:
y = 2(x^2 - 6x - 16) = 2(x - 8)(x + 2). Then its roots are x = -2 and x = 8.
Since d > e and 8 > -2, we conclude that d = 8 and e = -2.
We need to find the minimum of y = 2x^2 -12x - 32.
We can do this by finding the vertex: b
The equation of the axis of symmetry is x = - ----------
2a
-12
which here is x = - --------- = 3
2(2)
so f = 3.
Answer choice B is correct.
