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4 years ago

Alburry and wagga wagga are 130km apart. How many centimeters apart are they on a map with a scale factor of 1:250000?

Computers and Technology

1 answer:

lapo4ka [179]4 years ago

7 0

Answer:

The distance from Alburry to Wagga wagga on the map is 52 centimetres

Explanation:

The parameters given are

Actual distance between Alburry and Wagga wagga = 130 km.

130 km = 13,000,000 cm

Scale of map = 1:250000

Therefore;

1 unit on the map is equivalent to 250000 units in real measurements

Hence;

$130 \, km \equiv \dfrac{130 \, km}{250000} = \dfrac{130 \times 1000 \times 100 \, cm}{250000} = \dfrac{13,000,000 \, cm}{250000} = 52 \, cm$

Therefore, on the map, Alburry and Wagga wagga are 52 cm. apart.

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Mazyrski [523]

Answer:

The following statement are:

if(speed < 0) // if statement

{

reverseDrivers++; //if the speed is less than 0, then increment in "reverseDrivers"

}

else if(speed < 1) //else if statement

{

parkedDrivers++; //speed is less than 1, than increments in "parkedDrivers"

}

else if(speed < 40)

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slowDrivers++; //speed is less then 40, than increment in "slowDriver"

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else if(speed <= 65)

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Explanation:

From the following statement their are certain condition arises

If the speed is less than 0, then increments the “reverseDrivers” variable by 1.

If the speed is less than 1, then increments the “parkDriver” variable by 1.

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If speed is less than or equal to 40, then increment in "safeDriver" variable by 1.

Otherwise increment in "speeders"

7 0

3 years ago

Assume inputFile is a Scanner object used to read data from a text file that contains a number of lines. Each line contains an a

anzhelika [568]

Answer:

words.hasNext()

Explanation:

Given the code snippet below:

while (inputFile.hasNextLine()) {
String word = "";
String line = inputFile.nextLine();
Scanner words = new Scanner(line);
while (words.hasNext()) {
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System.out.println(word); }
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We have a inputFile Scanner object that can read data from a text file and we presume the inputFile has read several rows of data from the text file. So long as there is another line of input data available, the outer while loop will keep running. In each outer loop, one line of data will be read and assign to line variable (Line 3). Next, there is another Scanner object, words, which will take the current line of data as input. To get the last word of that line, we can use hasNext() method. This method will always return true if there is another tokens in its input. So the inner while loop will keep running so long as there is a token in current line of data and assign the current token to word variable. The word will hold the last token of current line of data upon exit from the inner loop. Then we can print the output (Line 8) which is the last word of the current line of data.

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3 years ago

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