Answer:
15$
Step-by-step explanation:
this is because if you use our formula of I= prt
we can substitute our varibles for our equation
I= 300 x 0.05 x 1
we turn 5 in 0.05 to represent out rate, due to this our rate would have to be Simplified into a percent then a decimal
after this if we now proceed through our equation we will get
I = 300 x 0.05 x 1
I = 15
-2-1 /2-4. -3/-2. Or 3/2. The slope is 3/2
Y-1=3/2(x-4)
Y-1=3/2x-6
Y= 3/2x -5
Answer:
The real solutions of f(x)=0 are: 0, 2, 5, 6
Step-by-step explanation:
We are given:
The graph of y = f(x)
We need to find all of the real solutions of f(x) = 0?
By looking at the graph we need to find the values of y when x =0
Looking at the graph, when x=0 we get
0, 2,5 and 6
So, the real solutions of f(x)=0 are: 0, 2, 5, 6
I am attaching the figure, that determines the answers.
Answer:
22.5 i think should be your answer
Answer:
The reason is that the since the segment AB and the new line passing through A are both parallel to the segment CD and all points on the new line and the segment AB are the same perpendicular distance from CD and the segment AB and the new line which follow the same direction share a common point, A, then the line drawn must fall on AB
Step-by-step explanation:
The given information are;
The shape of the quadrilateral ABCD = A parallelogram
The direction of the line to be drawn = Parallel to CD
A point on the line to be drawn = Point A
Therefore, given that ABCD is a parallelogram, we have;
Segment AB is parallel to segment CD
All points on AB are equidistant from all points on CD
The perpendicular distance of point A from the lime CD = The perpendicular distance of point B from the lime CD
The line to be drawn is also parallel to CD with point A located on the line, therefore, given that the length of a line is infinite, and all points on two parallel lines have equal perpendicular distance from the each other, the point B on the segment AB which has the same perpendicular distance as the point A from the segment CD will be located on the new line passing drawn passing through A and parallel to the segment CD then the new line drawn must coincide with the segment AB.
