Answer:
The correct answer is letter "A": commit with fallback.
Explanation:
American Professor Alfred A. Marcus (born 1950) in his book "<em>The Future of Technology Management and the Business</em>" (2015) describes that hedging may be a strategy to shield businesses from the rapidly evolving world they face as a result of the continuous implementation of technology in the market. According to Marcus, there are 5 hedge approaches that firms should implement:
- Gamble on the most probable:<em> work on the product with the highest success rate.
</em>
- Take the robust route: <em>invest in as many products as possible.
</em>
- Delay until further clarity emerges:<em> waiting for a proper moment to react in front of market changes.
</em>
- <u>Commit with a fallback</u>:<em> adapt according to the market.
</em>
- Try to shape the future:<em> innovate.</em>
Bridge communication is the best solution to continue two different building for the same company.
<u>Explanation:</u>
Bridge communication to be placed in both building.master device should be placed in one building where should be connected to a high-end server and the slave device should be placed in another device.
Both the master device and salve should have a subsequent TCPIP address. For example, if the master TCPIP address is 192.168.1.51 and the salve Tcpip address should be 192.168.1.52.
Very easy configure and communication is established. Both devices should be connected with nonstop current interruption. Once communication established speed depends on device capacity.
Answer:
Easy peasy, if you open Microsoft word and you click up at the top and you click the symbol as shown in A, then you click on inserted tab it will show up as B which is → symbol
So the answer is B →.
<u>Answer:</u>
I am writing <em>partial code in</em> <em>c++ to calculate weighted average</em>. The weighted average should be calculated based on multiplying the test score and its <em>respective weight and finally add all the test score.</em>
<u>Explanation:</u>
<em>int arrtestscore[100];</em>
<em>int arrweight[100];</em>
<em>int n;</em>
<em>double weightedavg;</em>
<em>cout<<”Enter the number of test score for which weighted average needs to be calculated”;</em>
<em>cin>>n;</em>
<em>for(int x = 0; x <n;x++)</em>
<em>{</em>
<em> cout<<”Enter test score :” + (x+1) ;</em>
<em> cin>>arrtestscore[x];</em>
<em> count<<”Enter the respective weight:”;</em>
<em> cin>>arrweight[x];</em>
<em>}</em>
<em>for (int i=0; i<n;i++)</em>
<em>{</em>
<em> weightedavg = weightedavg + (arrtestscore[i] * arrweight[i])</em>
<em>}</em>
<em>cout<<”weighted average = “ <<weightedavg; </em>
