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3 years ago

Find the radius of each sphere. a sphere with a volume of 1,767.1 m^3

Mathematics

1 answer:

Sonja [21]3 years ago

6 0

Answer:

Step-by-step explanation:

volume V=1,767.1 m³

also~4/3 πr³=1767.1

4/3×3.14 r³=1,767.1

r³=1767.1 ×3/12.56=5301.3/12.56

r=(5301.3.3÷12.56)^{1/3}≈7.50 m

You might be interested in

88 feet/second = 60 miles/hour. How many feet per second is 1 mile? (Hint: divide both side of the equation by the same amount.)

zalisa [80]

Answer:

1 mile/hour is equivalent to 1.47 feet/seconds

Step-by-step explanation:

Given

$88 ft/s= 60 miles/hr$

Required

Determine the equivalent of 1 mile/hour

$88\ ft/s= 60\ miles/hr$

Express 60 as 60 * 1

$88\ ft/s= 60 * 1\ mile/hr$

Divide both sides by 60

$\frac{88\ ft/s}{60}= \frac{60 * 1\ mile/hr}{60}$

$\frac{88\ ft/s}{60}= 1\ mile/hr$

Reorder

$1\ mile/hr = \frac{88\ ft/s}{60}$

Divide 88 by 60

$1\ mile/hr = 1.46666666667\ ft/s$

Approximate to 3 significant figures

$1\ mile/hr = 1.47\ ft/s$

Hence;

1 mile/hour is equivalent to 1.47 feet/seconds

8 0

2 years ago

Yo does anyone know how to do this?

Sonbull [250]

Answer:

The horizontal line is the x-axis and the vertical line is the y-axis.

Step-by-step explanation:

The horizontal line is the x-axis and the vertical line is the y-axis. It's a fact. You can graph the lines by inserting the equations using the graphing calculator, which is the tab next to the one you have right now ;)

3 0

2 years ago

Explain how you can solve the following scenario in two different ways. I owe my friend $16 and my mom owes me $25. how much mon

matrenka [14]

Answer:

Step-by-step explanation:

Given I owe my friend $16 and my mom owes me $25

step 1-->take back money from mom

Mom gives back you $25

Now you have $25

Step 2: return the money you owe to friend

you owe $16

You have $25 and return $16

Thus , money you will have = money you have - money you return

money you have = $25 - $16 = $9

Thus, you will have $9 , after all is settled.

7 0

3 years ago

In a random sample of 80 teenagers, the average number of texts handled in a day is 50. The 96% confidence interval for the mean

Nastasia [14]

Answer:

a) $\bar X =\frac{46+54}{2}=50$

And the margin of error is given by:

$ME= \frac{54-46}{2}= 4$

The confidence level is 0.96 and the significance level is $\alpha=1-0.96=0.04$ and the value of $\alpha/2 =0.02$ and the margin of error is given by:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$

We can calculate the critical value and we got:

$z_{\alpha/2} = 2.05$

And if we solve for the deviation like this:

$\sigma = ME * \frac{\sqrt{n}}{z_{\alpha/2}}$

And replacing we got:

$\sigma =4 *\frac{\sqrt{80}}{2.05} =17.45$

b) $ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}=2.05 *\frac{17.45}{\sqrt{160}}=2.828$

And as we can see that the margin of error would be lower than the original value of 4, the margin of error would be reduced by a factor $\sqrt{2}$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma$ represent the population standard deviation

n=80 represent the sample size

Solution to the problem

Part a

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

For this case we can calculate the mean like this:

$\bar X =\frac{46+54}{2}=50$

And the margin of error is given by:

$ME= \frac{54-46}{2}= 4$

The confidence level is 0.96 and the significance level is $\alpha=1-0.96=0.04$ and the value of $\alpha/2 =0.02$ and the margin of error is given by:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$

We can calculate the critical value and we got:

$z_{\alpha/2} = 2.05$

And if we solve for the deviation like this:

$\sigma = ME * \frac{\sqrt{n}}{z_{\alpha/2}}$

And replacing we got:

$\sigma =4 *\frac{\sqrt{80}}{2.05} =17.45$

Part b

For this case is the sample size is doubled the margin of error would be:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}=2.05 *\frac{17.45}{\sqrt{160}}=2.828$

And as we can see that the margin of error would be lower than the original value of 4, the margin of error would be reduced by a factor $\sqrt{2}$

5 0

2 years ago

Round 492.3069 to the nearest thousandth

Llana [10]

The answer is 492.307
The number after the thousandths is 9 - greater than 5 - so we round 6 up to 7.

4 0

3 years ago