All categories

3 years ago

Okay the answer for this

Mathematics

2 answers:

zepelin [54]3 years ago

7 0

Your answer is d, you can not use 6 and the equation be right.

swat323 years ago

5 0

D so yeeeeeeee byeeeee

You might be interested in

Can anyone help me with this problem?

Harman [31]

First one is correct choice

5 0

3 years ago

Is the integral ſ A. dr path independent if A = (2x - y)i + (x + y)j?

evablogger [386]

The integral is path-independent if we can find a scalar function f such that grad(f ) = A. This requires

$\dfrac{\partial f}{\partial x}=2x-y$

$\dfrac{\partial f}{\partial y}=x+y$

Take the first PDE and integrate both sides with respect to x to get

$f(x,y)=x^2-xy+g(y)$

where g is assumed to be a function of y alone. Differentiating this with respect to x gives

$\dfrac{\partial f}{\partial y}=-x+\dfrac{\mathrm dg}{\mathrm dy}=x+y\implies\dfrac{\mathrm dg}{\mathrm dy}=2x+y$

which would mean g is *not* a function of only y, but also x, contradicting our assumption. So the integral is path-dependent.

Parameterize the unit circle (call it C) by the vector function,

$\mathbf r(t)=\cos t\,\mathbf i+\sin t\,\mathbf j$

with t between 0 and 2π.

Note that this parameterization takes C to have counter-clockwise orientation; if we compute the line integral of A over C, we can multiply the result by -1 to get the value of the integral in the opposite, clockwise direction.

Then

$\mathrm d\mathbf r=-\sin t\,\mathbf i+\cos t\,\mathbf j$

and the (counter-clockwise) integral over C is

$\displaystyle\int_C\mathbf A\cdot\mathrm d\mathbf r$

$\displaystyle=\int_0^{2\pi}((2\cos t-\sin t)\,\mathbf i+(\cos t+\sin t)\,\mathbf j)\cdot(-\sin t\,\mathbf i+\cos t\,\mathbf j)\,\mathrm dt$

$\displaystyle=\int_0^{2\pi}1-\sin t\cos t\,\mathrm dt=2\pi$

and so the integral in the direction we want is -2π.

By the way, that the integral doesn't have a value of 0 is more evidence of the fact that the integral is path-dependent.

5 0

3 years ago

A certain drug is made from only two ingredients: compound A and compound B. There are 5 milliliters of compound A used for ever

ale4655 [162]

<h3>Answer: 410 mL </h3>

=====================================================

Explanation:

The ratio of A to B is 5:3

Multiply both parts by x to get 5x:3x

We need 5x parts of A and 3x parts of B

Adding those parts should get us 656 mL total

A+B = total

5x+3x = 656

8x = 656

x = 656/8

x = 82

Therefore, we need 5x = 5*82 = 410 mL of compound A

Also, we need 3x = 3*82 = 246 mL of compound B

In total, we have A+B = 410+246 = 656 mL which helps confirm the answer.

-----------

Side note: The ratio 410:246 reduces to 5:3 after dividing both parts by 82.

7 0

3 years ago

What is 1/3 rounded to

slavikrds [6]

The real amount is 3.333333333333333333333... so you can round it to 0.3

6 0

3 years ago

Question in the image v

Naily [24]

<1=55

<2=105

<3=55

Step-by-step explanation:

2.these are angles in a straight line so subtract 75 from 180 to get your answer

3.the angle missing from the triangle with 50 is equal to 75 since opposite angles at an x are equal

1.is equal to 55 since these are alternate or z angles with 3

6 0

3 years ago