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inn [45]
4 years ago
6

The function C(x) = 400x – 0.2x2 represents the total costs for a company to produce a product, where C is the total cost in dol

lars and x is the number of units sold. Which statement is true?
Mathematics
1 answer:
irakobra [83]4 years ago
7 0

Answer:

To determine the maxima and minima of the polynomial, differentiate the given based on x and equate to 0.

                                  C(x) = 400x - 0.2x²

                              dC(x) / dt = 400 - 0.4 x = 0 

The value of x is 1000. This is the value of the maxima. As the value of C(x) continously becomes lesser as the value of x is set higher, the minima is not identified. Substitute x to the original equation,

                              C(x) = (400)(1000) - 0.2(1000²) = $ 200,000

Thus, the answer is letter B. 

Step-by-step explanation:

Already Answered.

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Answer:

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6 0
4 years ago
What are 3 numbers whose product is about 9,000
Mice21 [21]
There are an infinite number of 3 number sets that will equal 9000, unless your looking for whole numbers.

If you want to find a set of whole numbers, first break 9000 into its factors:

5 * 5 * 5 * 3 * 3 * 2 * 2 * 2 = 9000

Now to find a set of 3 numbers, just combine some of the factors.
For example:

(5 * 5 * 5) * (3 * 3) * (2 * 2 * 2) = 9000
125 * 9 * 8 = 9000
6 0
3 years ago
The body of a dump truck is raised to empty a load of dirt. How high is the 10-inch body from the frame when it is tipped up at
s2008m [1.1K]
There is a special right triangle in this picture ( with angles 30°- 60°- 90° ). Sides of that triangle are: a, a/2 and a√3/2.
a = 10
h = a/2 
h = 10/2 = 5
Answer: A ) 5 inches
6 0
3 years ago
find the area of the shaded region of the radius is 9<br> Did I get the answer right
crimeas [40]

Answer:69.66

r=9 so diameter is 18, and the shape being a square you do 18 x 18 = 324

now the circles area is 254.34 now find the difference... and it is 69.66

Step-by-step explanation:

5 0
3 years ago
What is the radius of a circle whose equation is x2 y2 8x – 6y 21 = 0?
andrew11 [14]

we know that

the standard form of the equation of the circle is

(x-h)^{2} +(y-k)^{2}=r^{2}

where

(h,k) is the center of the circle

r is the radius of the circle

In this problem we have

x^{2} +y^{2} +8x-6y+21=0

<u>Convert to standard form</u>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(x^{2}+8x) +(y^{2}-6y)=-21

Complete the square twice. Remember to balance the equation by adding the same constants to each side.

(x^{2}+8x+16) +(y^{2}-6y+9)=-21+16+9

(x^{2}+8x+16) +(y^{2}-6y+9)=4

Rewrite as perfect squares

(x+4)^{2} +(y-3)^{2}=4

(x+4)^{2} +(y-3)^{2}=2^{2}

the center of the circle is (-4,3)

the radius of the circle is 2\ units

therefore

<u>the answer is</u>

the radius of the circle is 2\ units


8 0
3 years ago
Read 2 more answers
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