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Anestetic [448]
3 years ago
5

It’s in the picture if u can help I will be thankful

Mathematics
1 answer:
Delicious77 [7]3 years ago
6 0

Answer:

The length of LM,hypotenuse is 55.866ft

Step-by-step explanation:

Given that LN=39ft and MN=40ft so you can solve it using Pythogoras' Theorem:

side²+side² = hypo²

LN² + MN² = LM²

hypo² = 39²+40²

= 3121

LM = √3121

= 55.866ft (3d.p)

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In a certain region of space, the potential is given by v=2x−5x2y 3yz2. How much is the magnitude of the electric field at point
Masja [62]

The magnitude of the electric field at the point (-2, 2, 0) is 46.52 V/m

<h3>How to calculate the electric field?</h3>

Since in a certain region of space, the potential is given by v = 2x − 5x²y 3yz²,

The electric field, E = -grad(V) where grad(V) = (dV/dx)i + (dV/dy)j + (dV/dz)k

Since V = 2x − 5x²y + 3yz²

dV/dx = d(2x − 5x²y + 3yz²)/dx

= d2x/dx - d5x²y/dx + d3yz²/dx

= 2 - 10xy + 0

= 2 - 10xy

dV/dy = d(2x − 5x²y + 3yz²)/dy

= d2x/dy - d5x²y/dy + d3yz²/dy

= 0 - 5x² + 3z²

=  - 5x² + 3z²

dV/dz = d(2x − 5x²y + 3yz²)/dz

= d2x/dz - d5x²y/dz + d3yz²/dz

= 0 - 0 + 6z

=  6z

<h3>The electric field</h3>

So, E = -grad(V)

= -[(dV/dx)i + (dV/dy)j + (dV/dz)k]

= -[(2 - 10xy)i + (- 5x² + 3z²)j + (6z)k]

So, the electric field at (-2, 2, 0) is

E = -[(2 - 10xy)i + (- 5x² + 3z²)j + (6z)k]

E = -[(2 - 10(-2)(2))i + (- 5(2)² + 3(0)²)j + (6(0))k]

E = -[(2 + 40)i + (- 5(4) + 0)j + (0)k]

E = -[42i + (-20 + 0)j + (0)k]

E = -[42i - 20j + 0k]

E = -42i + 20j - 0k

<h3>The magnitude of the electric field</h3>

So, the magnitude of E at (-2, 2, 0) is

|E| = √[(-42)² + 20² + 0²]

=  √[1764 + 400 + 0]

= √2164

= 46.52 V/m

So, the magnitude of the electric field at the point (-2, 2, 0) is 46.52 V/m

Learn more about electric field here:

brainly.com/question/25751825

#SPJ12

3 0
2 years ago
Felicia places a rectangular rug that measures 10 feet by 11 feet in a triangular room with a base of 30 feet and height of 22 f
arsen [322]

Answer:

1. Area of rectangular rug is 110 ft^{2}

2. Area of triangular room is 330ft^{2}

Step-by-step explanation:

This problem bothers on the mensuration of flat shapes, rectangle and triangle.

step one

let us start by solving for the area of the rectangular rug

given data

Area A =  ?

Length l =  11 ft

Width w=  10 ft

we know that the area of a rectangle is expressed as

Area=Length * Width

substituting our given data we have

Area= 11*10\\Area= 110 ft^{2}

step two

let us  solve for the area of the triangular room

given data

Area A =  ?

base b =  30 ft

height  h=  22 ft

we know that the area of a triangle is expressed as

Area= \frac{1}{2} *base* height\\

substituting our given data we have

Area= \frac{1}{2} * 30* 22\\Area=\frac{660}{2} \\Area= 330 ft^{2}

8 0
3 years ago
On a certain marathon course, a runner reaches a big hill that is at least 10 miles into the race. If a total marathon is 26.2 m
maria [59]
If the marathon is 26.2 miles in total and the runner in 10 miles into the race then he has another 16.2 miles to go.

6 0
3 years ago
A rectangular sheet of metal has identical squares cut from each corner. The sheet is then bent along the dotted lines to form a
Reika [66]

The <em><u>correct answer</u></em> is:

3 inches.

Explanation:

We will use the Rational Roots Theorem to solve this.

First we can divide both sides of the equation by 4 in order to simplify it:

\frac{4x^3-72x^2+320x}{4}=\frac{420}[4} \\ \\x^3-18x^2+80=105

In order to solve this, we want the polynomial set equal to 0. To do this, subtract 105 from both sides:

x^3-18x^2+80x-105=105-105 \\x^3-18x^2+80x-105=0

The Rational Roots Theorem says that if p/q is a root of the polynomial, then p is a factor of the constant term and q is a factor of the leading coefficient. The constant term is -105. Drawing a factor tree, we find that the factors of this number are 1, -1, 3, -3, 5, -5, 7, -5, 15, -15, 21, -21. The leading coefficient is 1; its only factor is 1. This means p/q must be a whole number, and can be any of the factors of 105.

Using synthetic division, we try 1 in the box:

<u>1 |</u> 1 -18 80 -105

_______<u> 1</u>__<u> -17</u>___<u>63</u>__

1 -17 63 -42

Since there is a remainder, this is not a root. Trying -1,

<u>-1 |</u> 1 -18 80 -105

_______<u>-1</u>__<u> 19 </u>_<u>-99</u>_

1 -19 99 -204

This is not a root; in fact, it shows us that none of the negatives will be a factor, as the absolute values increase as we complete the synthetic division.

Trying 3,

3 | 1 -18 80 -105

________<u>3</u>__<u>-45</u>___<u>105</u>_

1 -15 35 0

Since there is no remainder, 3 is a root, and is the answer we are looking for.

3 0
3 years ago
Read 2 more answers
The distributive property is used to help simplify math experssions. True False
Mamont248 [21]
True is the answer
hope it helped
4 0
3 years ago
Read 2 more answers
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