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WINSTONCH [101]
3 years ago
15

A pair of equations is shown below: y = 7x - 8 y = 5x - 2 Part A: Explain how you will solve the pair of equations by substituti

on or elimination. Show all the steps and write the solution (5 points) Part B: If the two equations are graphed, at what point will the lines representing the two equations intersect? Explain your answer. (5 points)
Mathematics
1 answer:
yuradex [85]3 years ago
8 0
So, first of all you have to identify the two equations which are: y=7x-8 and y=5x-2. after identifying the two equation you can choose one of them to start with. I chose the first one and I'll use substitution method, which means I'll pug in numbers in the unknown variables to find the value of x. Y=7x-8, I'll substitute the value of y in the equation that I chose and plug in the value of the second equation. Y=7x-8 --> 5x-2=7x-8 (this is our new equation). After that I'll combine like terms. -2+8=7x-5x --> 6=2x  --> 6/2=x --> 3=x. So x=3 and that's the answer using substitution method. If the two points are graphed, they will intersect at the point (3,13). To see where the intersection of the line we can use a calculator to make it faster. So we plug in the points of the two lines in the calculator we graph and find the intersection point.
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The area of a rectangle is 45 square inches. One dimension is 5 inches. What is the perimeter
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Answer:

28 inches

Step-by-step explanation:

To begin, the area of a rectangle is base · height. Since we are given one of the sides already, you can make an equation to solve for the other value.

5 · x = 45

5x = 45

x = 9

A rectangle has two pairs of parallel sides, or in easier terms, two sets of sides that are the same. So, the perimeter is going to be two lengths plus two widths.

2 · 5 + 9 · 2 = 10 + 14 = 28

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2 years ago
Give two ratios with a description of the ratio relationship using the following information 15 mill teachers 35 female teachers
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we can say that there are 15 male teachers for every 35 female teacher

\stackrel{\textit{\large ratio 1}}{\cfrac{15}{35}\qquad \cfrac{male}{female}} ~\hspace{10em} \stackrel{\textit{\large ratio 2}}{\cfrac{\stackrel{3}{~~\begin{matrix} 15 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}{\underset{7}{~~\begin{matrix} 35 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}\implies \cfrac{3}{7}\qquad \cfrac{male}{female}}

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3 years ago
Lengths of segments
mina [271]

Answer:

Triangles:

10 m, 21 m, 29 m

10 m, 29 m, 37 m

Not triangles:

10 m, 14 m, 29 m

10 m, 29 m, 40 m

Step-by-step explanation:

For a triangle to exist, the sum of any two sides of a triangle must be greater than that of the third side.

Let us check each of the options.

Option 1: 10 m, 14 m, 29 m

The sum of lengths 10 m and 14 m must be greater than 29 m.

10 + 14 = 24 < 29

So, this is not a triangle.

Option 2: 10 m, 21 m, 29 m

10 + 21 = 31 > 29

21 + 29 = 50 > 10

29 + 10 = 39 > 21

Therefore, it is a triangle.

Option 3: 10 m, 29 m, 37 m

10 + 29 = 39 > 37

29 + 37 = 66 > 10

37 + 10 = 47 > 29

Therefore, it is a triangle.

Option 4: 10 m, 29 m, 40 m

10 + 29 =39 < 40

So, this is not a triangle.

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a will be the correct answer plzz tick that and win 1 lakh

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