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STALIN [3.7K]
3 years ago
5

PLEASE HELP URGENT!!!

Mathematics
1 answer:
Alenkinab [10]3 years ago
5 0

Answer: Choice A

3 over 12 multiplied by 7 over 11

(3/12) * (7/11)

=============================================

Explanation:

There are 3 yellow cars out of 2+7+3 = 12 total. The probability of selecting yellow is therefore 3/12. We can reduce this, but the answer choices decide not to, so we'll do the same.

After picking a yellow car, we have 12-1 = 11 left over. The amount of blue cars do not go down (because we haven't selected it yet). There are 7 blue cars out of the 11 total, so the probability of picking blue for this case is 7/11

Multiply the two fractions to get (3/12)*(7/11) which is a shorthand way of writing "3 over 12 multiplied by 7 over 11".

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What is the value of (f-g)(5)? a.-18 <br> b.-4 <br> c.16 <br> d.42
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PLZZ HELP ILL GIVE BRAINLIEST AND DO NOT TYPE NO LINK WITH YALL LAZY AHH
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D

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8 is LESS THAN 1/2x

so youd take those numbers and multiply by 1/2

C, B, and A are all under 8, so that would be wrong

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3 years ago
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Amy had homework for math,science,and history.she spent 1/3 of her time working on math and 1/4 of her time working on science.
Alja [10]
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science: 1/4 x 3/3=3/12

Now we can find the time she spent on history (I assume this is what you are looking for)

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8 0
2 years ago
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A rectangular area is to be fenced in with 300 feet of chicken wire. find the maximum area that can be enclosed.
GarryVolchara [31]
Let the lengths of the sides of the rectangle be x and y. Then A(Area) = xy and 2(x+y)=300. You can use substitution to make one equation that gives A in terms of either x or y instead of both.

2(x+y) = 300
x+y = 150
y = 150-x

A=x(150-x) <--(substitution)

The resulting equation is a quadratic equation that is concave down, so it has an absolute maximum. The x value of this maximum is going to be halfway between the zeroes of the function. The zeroes of the function can be found by setting A equal to 0:
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So halfway between the zeroes is 75. Plug this into the quadratic equation to find the maximum area.

A=75(150-75)
A=75*75
A=5625

So the maximum area that can be enclosed is 5625 square feet.
6 0
3 years ago
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