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earnstyle [38]
3 years ago
14

Identify the steps you would take to solve each equation. Then solve 7y + 6 + 4y + 13 = 26​

Mathematics
1 answer:
andriy [413]3 years ago
5 0

Answer:

7/11

Step-by-step explanation:

7y +6+4y+13=26

firstly collect like terms

7y+4y+6+13=26

11y+19=26

11y=26-19

11y=7

then divide through by 11

y=7/11

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Translate and solve 5 greater than m is no more than 65
Nadusha1986 [10]

Answer:

m ≤ 60    (look at the picture)

Step-by-step explanation:

<em>5 greater than m is no more than 65</em>

m + 5 ≤ 65             <em>subtract 5 from both sides</em>

m + 5 - 5 ≤ 65 - 5

m ≤ 60

6 0
3 years ago
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What’s the area of this
aleksandr82 [10.1K]

Answer:

1500

Step-by-step explanation:

10 * 10 = 100

35*40 = 1400

Add them

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3 years ago
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Susan makes ribbon bows for a local pet store. She purchased 25 yards of ribbons and used 15 7/8 yards to make a dozen bows. How
CaHeK987 [17]

Answer:

9 1/8 ribbon would be remaining

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2 years ago
A bag contains 4 blue marbles and 2 yellow marbles. Two marbles are randomly chosen (the first marble is NOT replaced before dra
VMariaS [17]

Answer:

0.4 = 40% probability that both marbles are blue.

0.0667 = 6.67% probability that both marbles are yellow.

53.33% probability of one blue and then one yellow

If you are told that both selected marbles are the same color, 0.8571 = 85.71% probability that both are blue

Step-by-step explanation:

To solve this question, we need to understand conditional probability(for the final question) and the hypergeometric distribution(for the first three, because the balls are chosen without being replaced).

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

What is the probability that both marbles are blue?

4 + 2 = 6 total marbles, which means that N = 6

4 blue, which means that k = 4

Sample of 2, which means that n = 2

This is P(X = 2). So

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 2) = h(2,6,2,4) = \frac{C_{4,2}*C_{2,0}}{C_{6,2}} = 0.4

0.4 = 40% probability that both marbles are blue

What is the probability that both marbles are yellow?

4 + 2 = 6 total marbles, which means that N = 6

2 yellow, which means that k = 2

Sample of 2, which means that n = 2

This is P(X = 2). So

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 2) = h(2,6,2,2) = \frac{C_{2,2}*C_{4,0}}{C_{6,2}} = 0.0667

0.0667 = 6.67% probability that both marbles are yellow.

What is the probability of one blue and then one yellow?

Total is 100%.

Can be:

Both blue(40%)

Both yellow(6.67%)

One blue and one yellow(x%). So

40 + 6.67 + x = 100

x = 100 - 46.67

x = 53.33

53.33% probability of one blue and then one yellow.

If you are told that both selected marbles are the same color, what is the probability that both are blue?

Conditional probability.

Event A: Both same color

Event B: Both blue

Probability of both being same color:

Both blue(40%)

Both yellow(6.67%)

This means that P(A) = 0.4 + 0.0667 = 0.4667

Probability of both being the same color and blue:

40% probability that both are blue, which means that P(A \cap B) = 0.4

Desired probability:

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.4}{0.4667} = 0.8571

If you are told that both selected marbles are the same color, 0.8571 = 85.71% probability that both are blue

8 0
3 years ago
Which of the following is not a requirement of a standard form equation Ax+By=C? a)A ≥ 0. b)B ≥ 0. c)A and B are not both 0. d)A
Ghella [55]
<h2>Answer:</h2>

The following which is not a requirement of a standard form of equation Ax+By=C is:

        b)   B ≥ 0    

<h2>Step-by-step explanation:</h2>

We know that the standard equation of a line is given by:

        Ax+By=C

where A,B and C are integers and A is taken to be a non-negative integer i.e. (A≥0) also the greatest common factor of A,B and C is: 1.

Also A and B can't be both zero.

       Hence, the correct option is:

                Option: b

7 0
3 years ago
Read 2 more answers
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