Please help !!!! Thank you

Ramona deposited $4,190.51 into a savings account with an interest rate of 5.2% compounded twice a year. About how long will it

kap26 [50]

<span>A = P(1+r/2)^2t A/P = (1+r/2)^2t ln(A/P) = 2t ln((1+r/2)) ln(A/P)/ln(1+r/2) =2t ln(9000/4190.51)/ln(1+0.052/2)=2t t=15 yrs therfore ans is C.14 years ,11 months</span>

7 0

3 years ago

Express the following as a fraction in its simplest form.

pychu [463]

Given:

Consider the given expression is:

$\dfrac{h+f}{3}+\dfrac{f+k}{2}+\dfrac{4h-k}{5}$

To find:

The simplified form of the given expression.

Solution:

We have,

$\dfrac{h+f}{3}+\dfrac{f+k}{2}+\dfrac{4h-k}{5}$

Taking LCM, we get

$=\dfrac{10(h+f)+15(f+k)+6(4h-k)}{30}$

$=\dfrac{10h+10f+15f+15k+24h-6k}{30}$

$=\dfrac{34h+25f+9k}{30}$

Therefore, the required simplified fraction for the given expression is $\dfrac{34h+25f+9k}{30}$ .

6 0

3 years ago

What’s the correct answer for this?

VMariaS [17]

Answer:

Second option is the correct answer

$(x+11)^2+(y+6)^2 = 324$

Step-by-step explanation:

$x^{2} +12y+22x+y^2-167=0\\x^{2}+22x +y^2 +12y-167=0\\(x^{2}+22x +121)-121 +(y^2 +12y+36)-36-167=0\\(x+11)^2+(y+6)^2-324 = 0\\\huge\red{\boxed{(x+11)^2+(y+6)^2 = 324}}\\$

5 0

3 years ago

Read 2 more answers

What is the quotient of the following division problem?

Whitepunk [10]

Answer:

D. 10r7

Explaination:

9 goes into 97 10 times, and has a remainder of 7

7 0

3 years ago

A random sample of n 1 = 249 people who live in a city were selected and 87 identified as a democrat. a random sample of n 2 = 1

kvasek [131]

Answer:

$CI=\{-0.2941,-0.0337\}$

Step-by-step explanation:

Assuming conditions are met, the formula for a confidence interval (CI) for the difference between two population proportions is $\displaystyle CI=(\hat{p}_1-\hat{p}_2)\pm z^*\sqrt{\frac{\hat{p}_1(1-\hat{p}_1)}{n_1}+\frac{\hat{p}_2(1-\hat{p}_2)}{n_2}$ where $\hat{p}_1$ and $n_1$ are the sample proportion and sample size of the first sample, and $\hat{p}_2$ and $n_2$ are the sample proportion and sample size of the second sample.

We see that $\hat{p}_1=\frac{87}{249}\approx0.3494$ and $\hat{p}_2=\frac{58}{113}\approx0.5133$ . We also know that a 98% confidence level corresponds to a critical value of $z^*=2.33$ , so we can plug these values into the formula to get our desired confidence interval:

$\displaystyle CI=(\hat{p}_1-\hat{p}_2)\pm z^*\sqrt{\frac{\hat{p}_1(1-\hat{p}_1)}{n_1}+\frac{\hat{p}_2(1-\hat{p}_2)}{n_2}}\\\\CI=\biggr(\frac{87}{249}-\frac{58}{113}\biggr)\pm 2.33\sqrt{\frac{\frac{87}{249}(1-\frac{87}{249})}{249}+\frac{\frac{58}{113}(1-\frac{58}{113})}{113}}\\\\CI=\{-0.2941,-0.0337\}$

Hence, we are 98% confident that the true difference in the proportion of people that live in a city who identify as a democrat and the proportion of people that live in a rural area who identify as a democrat is contained within the interval {-0.2941,-0.0337}

The 98% confidence interval also suggests that it may be more likely that identified democrats in a rural area have a greater proportion than identified democrats in a city since the differences in the interval are less than 0.

5 0

2 years ago