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marishachu [46]

4 years ago

5

Which linear function includes the points (3,9) and (-2,-11)

2 answers:

Murrr4er [49]4 years ago

7 0

$General\ equation\ for\ line\ in\ slope\ intercept\ form:\\\\y=ax+b\\\\To\ find\ a\ and\ b\ substitude\ points\ (3,9),\ (-2,-11)\ into\ equation\\\\ \left \{ {{9=3a+b}\ \ \ \ \atop {-11=-2a+b\ |*-1}} \right.\\\\ \left \{ {{9=3a+b}\ \ \ \ \atop {11=2a-b}} \right.\\+----\\\\Addition\ method\\\\20=5a\ \ |:5\\\\a=4\\ b=9-3a\\b=9-3*4=9-12=-3\\\\Answer\ y=4x-3
$

Charra [1.4K]4 years ago

3 0

(2,1) is the answer

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3 years ago

Tyee answered 126 questions correctly on his multiple choice history final that had a total of 200 problems. What percentage of

notsponge [240]

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Like 3/5? Or something?

Step-by-step explanation:

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3 years ago

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Find the fourth-degree polynomial function with zeros 4, -4, 4i , and -4i . Write the function in factored form.

Iteru [2.4K]

Given:

A fourth-degree polynomial function has zeros 4, -4, 4i , and -4i .

To find:

The fourth-degree polynomial function in factored form.

Solution:

The factor for of nth degree polynomial is:

$P(x)=(x-a_1)(x-a_2)...(x-a_n)$

Where, $a_1,a_2,...,a_n$ are n zeros of the polynomial.

It is given that a fourth-degree polynomial function has zeros 4, -4, 4i , and -4i. So, the factor form of given polynomial is:

$P(x)=(x-4)(x-(-4))(x-4i)(x-(-4i))$

$P(x)=(x-4)(x+4)(x-4i)(x+4i)$

$P(x)=(x-4)(x+4)(x^2-(4i)^2)$ $[\because a^2-b^2=(a-b)(a+b)]$

On further simplification, we get

$P(x)=(x-4)(x+4)(x^2-4^2i^2)$

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6 0

3 years ago

Is the following table proportional or non proportional (3,5) (6,10) (9,15) (12,20)

Sholpan [36]

Answer:

This is proportional

Step-by-step explanation:

3,5

6,10

9,15

12,20

The x's go by +3

The y's go by +5

Hope this helped!

7 0

3 years ago