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Varvara68 [4.7K]
3 years ago
15

A test is normally distributed with a mean of 70 and a standard deviation of 10. Todd scores a 55 on the test. Select the answer

from the drop-down menu to correctly complete the statement. Based on the mean of 70 and his raw score of 55, Todd’s z-score must be
Mathematics
1 answer:
Jlenok [28]3 years ago
6 0

Answer:

Todd's Z-score is - 0.27    

Step-by-step explanation:

<u><em>Explanation</em></u>:-

<u><em>Step(i)</em></u>:-

Given data A test is normally distributed with a mean of 70 and a standard deviation of 10.

<em>Mean of the population 'μ' = 70 </em>

<em>Standard deviation of the Population ' σ ' = 10</em>

<em>let 'x' be the random variable in normally distributed</em>

<u><em>Step(ii)</em></u>:-

<em>Given raw score  'x' = 55</em>

Todd's Z-score

                      Z = \frac{x-mean}{S.D}

                     Z = \frac{55-70}{55}

                     Z = -0.27

<u><em>Final answer</em></u>:-

<em>Todd's Z-score is - 0.27        </em>            

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Answer:

450

Step-by-step explanation:

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4 0
3 years ago
Three friends went to a book shop the first bought three bros and four pencils for $30.00. The second bought two Bros and five p
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Answer:

total 66$

Step-by-step explanation:

let price of bro s be x and pencil be y

according to Qn

at 1 cond

3x+4=30____(1)

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3 years ago
The response to a question has three alternatives: A, B, and C. A sample of 120 responses provides 60 A, 12 B, and 48 C. Show th
zimovet [89]

Answer:

CLASS     FREQUENCIES     RELATIVE FREQUENCIES

A                        60                                 0.5

B                        12                                  0.1

C                        48                                 0.4

TOTAL              120                                  1

Step-by-step explanation:

Given that;

the frequencies of there alternatives are;

Frequency A = 60

Frequency B = 12

Frequency C = 48

Total = 60 + 12 + 48 = 120

Now to determine our relative frequency, we divide each frequency by the total sum of the given frequencies;

Relative Frequency A = Frequency A / total = 60 / 120 = 0.5

Relative Frequency B = Frequency B / total = 12 / 120 = 0.1

Relative Frequency C = Frequency C / total = 48 / 120 = 0.4

therefore;

CLASS     FREQUENCIES     RELATIVE FREQUENCIES

A                        60                                 0.5

B                        12                                  0.1

C                        48                                 0.4

TOTAL              120                                  1

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we know that

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C=120^o

substitute the given values

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