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Sedbober [7]
3 years ago
7

URGENT! Please and Thanks :)

Mathematics
1 answer:
eimsori [14]3 years ago
6 0
For this case we will define the following:
 A, B: are the values of the triangle angles
 a, b: are the values of the lengths of the sides opposite the angles A, B.
 We then have to use the law of the sine:
 \frac{sinB}{b} = \frac{sinA}{a}
 Clearing the angle B we have:
 sinB = \frac{sinA}{a}*b
 B = arcsin(\frac{sinA}{a}*b)
 Substituting values we have:
 B = arcsin(\frac{sin113}{200}*134)
 B = 38.08
 Answer:
 
the following is true:
 
A. angle B=38.08 degrees 

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3x-18 &gt;3 <br> need to solve for X
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What is 27.35 expressed as a mixed number?
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4 0
3 years ago
Suppose you want to build a fish tank in the shape of a right rectangular box with square base and no top which will hold 6 cubi
AlekseyPX
You must develop a cost function C(x) and then minimize its value.
How much dwill the glass cost?  It's $1 per sq ft, and the total area of the glass is 4(xh), where x is the length of one side of the base and h is the height of the tank.  The area of the metal bottom is x^2, which we must multiply by $1.50 per sq ft. 

This cost function will look like this:  C(x) = 4($1/ft^2)xh + ($1.50/ft^2)x^2

but we know that (x^2)h= 6 cu ft, or h = (6 cu ft) / (x^2).  Subst. this last result into the C(x) equation, immediately above:

C(x) = 4($1/ft^2)x[6 ft^3 / x^2] + ($1.50/ft^2)x^2

Let's focus on the numerical values and ditch the units of measurement for now:

C(x) = 4x(4/x^2) + 1.50x^2, or

C(x) = 16/x + 1.5x^2

Differentiate this with respect to x:

C '(x) = -16 / x^2 + 3 x

Set this equal to 0 and solve for x:    -16/x^2 = -3x, or 16 = 3x^3

Then x^3 = 16/3, and x = 5 1/3 ft.  We already have the formula  

(x^2)h= 6 cu ft, so if x = 5 1/3, or 16/3, then (16/3)^2 h = 6, or

h = 6 / [16/3]^2.

h = 6 (9/256) = 0.21 ft.  While possible, this h = 0.21 ft seems quite unlikely.


Please work through this problem yourself, making sure you understand each step.  If questions arise, or if you find an error in my approach, please let me know.

Once again:
1.  Write a formula for the total cost of the material used:  4 sides of dimensions xh each, plus 1 bottom, of dimensions x^2.  Include the unit prices:  $1 per square foot for the sides and $1.50 per square foot for the bottom.
2.  Differentiate C(x) with respect to x.
3.  Set C '(x) = 0 and solve for the critical value(s).
4.  Calculate h from your value for x.
5.  Write the dimensions of the tank:  bottom:  x^2; height:  h
4 0
3 years ago
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