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sasho [114]
3 years ago
15

The price of products may increase due to inflation and decrease due to depreciation. Derek is studying the change in the price

of two products, A and B, over time. The price f(x), in dollars, of product A after x years is represented by the function below: f(x) = 12500(0.82)x Part A: Is the price of product A increasing or decreasing and by what percentage per year? Justify your answer. (5 points) Part B: The table below shows the price f(t), in dollars, of product B after t years: t (number of years) 1 2 3 4 f(t) (price in dollars) 5600 3136 1756.16 983.45 Which product recorded a greater percentage change in price over the previous year? Justify your answer. (5 points)
Mathematics
1 answer:
BaLLatris [955]3 years ago
3 0
For product A, the product is increasing, for the bigger the number you plug into x (due to the fact that the numbers become bigger because of the time: year 1, year 2, etc)
Product A is 82% change rate, while 
product B is 983.45/4 = 245.8625,  1756.16/3 = <span>585.3867</span>
Product B is 245.8625/585.3867
product B is 42% change rate

Product A change rate is higher than Product B by 40%

hope this helps
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When a point moves right on a coordinate plane,<br> what happens to its x-value?
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4 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
ycow [4]

Answer: 0) 0.22

              1) 0.20

              2) 0.12

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<u>Step-by-step explanation:</u>

The total frequency is 33+30+18+21+42+6 = 150.  This means they ran the experiment 150 times.  The probability (P) is calculated by the satisfactory number of outcomes (frequency) divided by the total number of experiments/outcomes (total frequency):

\begin{array}{c|c||lc}\underline{x}&\underline{f}&\underline{f\div 150}&\underline{\text{P}}\\0&33&33\div 150=&0.22\\1&30&30\div150=&0.20\\2&18&18\div 150=&0.12\\3&21&21\div 150=&0.14\\4&42&42\div 150=&0.28\\5&6&6\div 150=&0.04\end{array}\right]

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