Solve for x 4x^2+28x+49=0

1 answer:

4 0

4 x^2 + 28 x + 49 = 0
Divide both sides by 4:
x^2 + 7 x + 49/4 = 0
Write the left hand side as a square:
(x + 7/2)^2 = 0
Take the square root of both sides:
x + 7/2 = 0
Subtract 7/2 from both sides:
Answer: x = -7/2

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Solve for v: -10=-5/4v

vagabundo [1.1K]

Answer:

v = 8

Step-by-step explanation:

-10= -5/4v first multiply both sides of the equation by -4/5

-10(-4/5) = v this cancels out the right side.

multiply the left side.

so you are left with 40/5 = v

next, simplify you will get 8=v

8 0

2 years ago

Read 2 more answers

What is the solution to the system of equations?

natka813 [3]

Answer:

Step-by-step explanation:

There is an error in the question. The table does not show two linear functions. y₁ is a linear function, but y₂ is not a straight line. It makes a bend at (-6,1).

Line 1 goes through (-12,-3) and (0,5).

slope = (5-(-3))/(0-(-12)) = 2/3

y-intercept = 5

y₁ = (2/3)x + 5

Line 2 goes through (-12,-2) and (-6,1).

slope = (1-(-2))/(-6-(-12)) = 1/2

y₂ = (1/2)x + 4

(2/3)x + 5 = (1/2)x + 4

x = -6

y = (2/3)x + 5 = 1

Solution: (-6,1)