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Ronch [10]
3 years ago
12

Gary works at a store on the weekends. Last weekend, he earned $56 for working a total of 7 hours. How much did Gary earn per ho

ur?
Mathematics
2 answers:
Andrew [12]3 years ago
7 0

Answer:

8$ an hour

Step-by-step explanation:

56 divided by 7 is 8

pishuonlain [190]3 years ago
4 0

Answer:

$8 per hour

Step-by-step explanation:

You just divide the pay check by the number of hours worked and you get the solution. Hopefully this helps you!

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Y = 2x + 3<br><br><br> y = 1/2 x – 3<br><br><br> y = –2x – 3<br><br><br> y = 1/2 x + 3
vodka [1.7K]

Answer:

y = 1/2 x + 3

Step-by-step explanation:

the positive 3 is the y intercept and the positive 1/2 is rise over run up-1 & 2 to the right

5 0
3 years ago
Determine whether or not the following graph represents two quantities that are proportional to each other. Explain your reasoni
m_a_m_a [10]

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Not proportional.

Step-by-step explanation:

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4 0
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A personality test is designed to determine what two things?
Vikentia [17]

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6 0
3 years ago
4 - (-18) = 4 - (-18) =
VashaNatasha [74]

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8 0
3 years ago
A randomized controlled study was designed to test whether regular drinking of cranberry juice can prevent the recurrence of uri
Kamila [148]

Answer:

1. The chi-squared statistic = 10.36

The degrees of freedom = 17

The p-value for the test = 0.89

2. The range of the p-value from the Chi squared table = 0.75 < p-value < 0.90

Step-by-step explanation:

1. The Chi squared test is given as follows;

\chi ^{2} = \sum \dfrac{\left (Observed - Expected  \right )^{2}}{Expected  }

Therefore,

                              UTI   No UTI    %     Total

Cranberry juice       8           42      84     50

Lactobacillus          19          30       61     49

Control                    18          30      60    50

The chi-squared statistic is given as follows;

\chi ^{2} = \dfrac{\left (8- 18\right )^{2}}{18} +  \dfrac{\left (42 - 30\right )^{2}}{30} = 10.36

The chi-squared statistic = 10.36

The degrees of freedom, df = 18 - 1 = 17 since the all of the expected count have a minimum value of 18

With the aid of the calculator we find the p value as p as follows;

p = 0.9 - \dfrac{10.36 - 10.085}{12.972 - 10.085} \times (0.9 - 0.75)

The p-value for the test = 0.89  

2. The range of the p-value from the Chi squared table is given as follows;

0.75 < p-value < 0.90.

5 0
3 years ago
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