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Law Incorporation [45]
3 years ago
11

Problem 7-12 don't understand it so can I have answer please.

Mathematics
2 answers:
Elanso [62]3 years ago
7 0
The 225 students that did not bring their lunch are 75% of the school, so find 1/3 of the 75% to get the 25%, then add the two and your final answer is 300.
katovenus [111]3 years ago
4 0
The answer is to your question is -21
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State whether the following number is divisible by 2,5, or 10. 215
adoni [48]

Answer

215 can only be divided by 5

4 0
2 years ago
The equation 201.50=f+6.50(21) represents the cost of printing the shirts at a second printing company. Find the solution to the
AveGali [126]

Answer:

f = 65

Setup cost = 65

Step-by-step explanation:

Given the equation : 201.50=f+6.50(21)

Solving for f:

201.50 = f + 136.50

201.50 - 136.50 = f

f = 65

The equation above is written in the form a slope intercept function where,, 6.50 is the gradient and X equals the number of shirts, The total cost of printing is 201.50

f is the intercept and represents the initial fee or setup cost. Hence, the setup. Cost = 65

5 0
2 years ago
What is the first step to finding the equation of a line when 2 points are known?
vladimir1956 [14]
The first step to finding the equation of a line when 2 points are known....
the first step would be to use the slope formula to find the slope of the line
5 0
3 years ago
Remember to show work and explain. Use the math font.
MrMuchimi

Answer:

\large\boxed{1.\ f^{-1}(x)=4\log(x\sqrt[4]2)}\\\\\boxed{2.\ f^{-1}(x)=\log(x^5+5)}\\\\\boxed{3.\ f^{-1}(x)=\sqrt{4^{x-1}}}

Step-by-step explanation:

\log_ab=c\iff a^c=b\\\\n\log_ab=\log_ab^n\\\\a^{\log_ab}=b\\\\\log_aa^n=n\\\\\log_{10}a=\log a\\=============================

1.\\y=\left(\dfrac{5^x}{2}\right)^\frac{1}{4}\\\\\text{Exchange x and y. Solve for y:}\\\\\left(\dfrac{5^y}{2}\right)^\frac{1}{4}=x\qquad\text{use}\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\\\\\dfrac{(5^y)^\frac{1}{4}}{2^\frac{1}{4}}=x\qquad\text{multiply both sides by }\ 2^\frac{1}{4}\\\\\left(5^y\right)^\frac{1}{4}=2^\frac{1}{4}x\qquad\text{use}\ (a^n)^m=a^{nm}\\\\5^{\frac{1}{4}y}=2^\frac{1}{4}x\qquad\log_5\ \text{of both sides}

\log_55^{\frac{1}{4}y}=\log_5\left(2^\frac{1}{4}x\right)\qquad\text{use}\ a^\frac{1}{n}=\sqrt[n]{a}\\\\\dfrac{1}{4}y=\log(x\sqrt[4]2)\qquad\text{multiply both sides by 4}\\\\y=4\log(x\sqrt[4]2)

--------------------------\\2.\\y=(10^x-5)^\frac{1}{5}\\\\\text{Exchange x and y. Solve for y:}\\\\(10^y-5)^\frac{1}{5}=x\qquad\text{5 power of both sides}\\\\\bigg[(10^y-5)^\frac{1}{5}\bigg]^5=x^5\qquad\text{use}\ (a^n)^m=a^{nm}\\\\(10^y-5)^{\frac{1}{5}\cdot5}=x^5\\\\10^y-5=x^5\qquad\text{add 5 to both sides}\\\\10^y=x^5+5\qquad\log\ \text{of both sides}\\\\\log10^y=\log(x^5+5)\Rightarrow y=\log(x^5+5)

--------------------------\\3.\\y=\log_4(4x^2)\\\\\text{Exchange x and y. Solve for y:}\\\\\log_4(4y^2)=x\Rightarrow4^{\log_4(4y^2)}=4^x\\\\4y^2=4^x\qquad\text{divide both sides by 4}\\\\y^2=\dfrac{4^x}{4}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\y^2=4^{x-1}\Rightarrow y=\sqrt{4^{x-1}}

6 0
3 years ago
Find the highest common factor of 14(3x+1)^ and 7(3x+1)​
ddd [48]

Answer:

The highest common factor is 7(3x+1)

Step-by-step explanation:

Here, we want to find the highest common factor of both expressions

As we can see, the highest common factor of 7 and 14 is 7

Now, we have the second expression which is (3x+1)

No matter what the first expression is raised to, it still stands that the highest common factor we shall have there is 3x+ 1 as concerns the term

inside the bracket

Thus, the highest common factor of both terms is 7(3x + 2)

5 0
3 years ago
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