<u>Answer-</u>
<em>The coordinates of the orthocenter of △JKL is (-4, 8)</em>
<u>Solution-</u>
The orthocenter is the point where all three altitudes of the triangle intersect. An altitude is a line which passes through a vertex of the triangle and is perpendicular to the opposite side.
For a right angle triangle, the vertex at the right angle is the orthocentre of the triangle.
Here we are given the three vertices of the triangle are J(-4,-1), K(-4,8) and L(2,8)
If the triangle JKL satisfies Pythagoras Theorem, then triangle JKL will be a right angle triangle.
Applying distance formula we get,

As,




Therefore, the vertex at K (-4, 8) is the orthocentre.
To put a slope-intercept into standard form, you have to first cancel out the fractions. So:

Turns into:

Simplify:

Distribute:

Since you want to get x and y on the same side, you subtract 12x from both sides to get:

So, your answer is
C. Hope this all made sense! If it doesn't you know where to get a hold of me, so just dm me. Or if you more problems.
Answer:
1.a=5cm
Surface area :6a²=6×5²=150cm²
2.r=3cm
h=5cm
total surface area of cylinder =2πr(r+h)
=2π×3(3+5)=48π cm²
3.
l=4m
b=5m
h=2m
now.surface area =2(lb+lh+bh)
=2(4*5+4*2+5*2)
=76m²
4.
r=6cm
surface area =4πr²=4*π*6²=144πcm²
5.
slant height (S)=8cm
length =breadth=(L)=4cm
Surface area of pyramid =area of base + 2* area of trainglular face
=L²+2*S*L
=4²+2*8*4
=80cm²
Answer: I believe the answer is 59 Items
Step-by-step explanation: 28 + 19= 47
47+12= 59
Step-by-step explanation:
If you were to round 398 to the nearest hundred, you would get 400. that's only 2 off of 398. when you add 400 + 257 that would equal 857 because 4 + 2= 6 and then the other two digits on 400 are zeros so 5 and 7 stay the same. with 857, you must now subtract 2 because you added 2 earlier. 857 - 2 = 855.