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inn [45]
3 years ago
11

Which is a good comparison of the estimated sum and the actual sum of 7 9/12 + 2 11/12?

Mathematics
2 answers:
natta225 [31]3 years ago
8 0
7 9/12 = 7.75
2 11/12 = 2.917

So we can round both of these up.

7.75 rounds to 8
2.917 rounds to 3

8 + 3 = 11

So the estimated sum is 11.

7 9/12 + 2 11/12 = 10 2/3

So the actual sum is 10 2/3.

The estimated sum is a pretty good estimate to the original number.
Flauer [41]3 years ago
6 0
7 9/12 + 2 11/12
((12*7)+9)/12+((12*2)+11)/12

93/12+35/12

128/12 divide by 2

(128/2)/(12/2)

64/6 divide by 2

(64/2)/(6/2)

32/3

10 2/3
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What are the coordinates of the orthocenter of △JKL with vertices at J(−4, −1) , K(−4, 8) , and L(2, 8) ?
Sati [7]

<u>Answer-</u>

<em>The coordinates of the orthocenter of △JKL is (-4, 8)</em>

<u>Solution-</u>

The orthocenter is the point where all three altitudes of the triangle intersect. An altitude is a line which passes through a vertex of the triangle and is perpendicular to the opposite side.

For a right angle triangle, the vertex at the right angle is the orthocentre of the triangle.

Here we are given the three vertices of the triangle are  J(-4,-1), K(-4,8) and L(2,8)

If the triangle JKL satisfies Pythagoras Theorem, then triangle JKL will be a right angle triangle.

Applying distance formula we get,

JK^2= (-4+4)^2+ (8+1)^2=0+81=81\\\\KL^2= (-4-2)^2+ (8-8)^2=36+0=36\\\\JL^2= (-4-2)^2+(8+1)^2=36+81=117

As,

\Rightarrow 117=81+36

\Rightarrow JL^2=JK^2+KL^2

\Rightarrow \text{JKL is a right angle triangle}

\Rightarrow \angle K=90^{\circ}

Therefore, the vertex at K (-4, 8) is the orthocentre.

3 0
3 years ago
How do you write y=25x-56 in standard form?
Tcecarenko [31]
To put a slope-intercept into standard form, you have to first cancel out the fractions. So:
y = \frac{2}{5}x - \frac{5}{6}

Turns into:
(5)(6)y = (\frac{2}{5}x - \frac{5}{6})(5)(6)

Simplify:
30y =  (\frac{2}{5}x - \frac{5}{6})(30)

Distribute:
30y = 12x- 25

Since you want to get x and y on the same side, you subtract 12x from both sides to get:
-12x+30y = -25

So, your answer is C. Hope this all made sense! If it doesn't you know where to get a hold of me, so just dm me. Or if you more problems.
6 0
4 years ago
Find the surface area of the following figures.<br><br>with solution please. T-T​​
Airida [17]

Answer:

1.a=5cm

Surface area :6a²=6×5²=150cm²

2.r=3cm

h=5cm

total surface area of cylinder =2πr(r+h)

=2π×3(3+5)=48π cm²

3.

l=4m

b=5m

h=2m

now.surface area =2(lb+lh+bh)

=2(4*5+4*2+5*2)

=76m²

4.

r=6cm

surface area =4πr²=4*π*6²=144πcm²

5.

slant height (S)=8cm

length =breadth=(L)=4cm

Surface area of pyramid =area of base + 2* area of trainglular face

=L²+2*S*L

=4²+2*8*4

=80cm²

7 0
3 years ago
There were 28 hats, 12 bicycles, and 19 teddy bears sold during a neighborhood yard sale. How many items were sold at the neighb
jasenka [17]

Answer: I believe the answer is 59 Items


Step-by-step explanation: 28 + 19= 47

47+12= 59


8 0
3 years ago
Explain how to find 398 + 257 with mental math and with the standard algorithm.
klasskru [66]

Step-by-step explanation:

If you were to round 398 to the nearest hundred, you would get 400. that's only 2 off of 398. when you add 400 + 257 that would equal 857 because 4 + 2= 6 and then the other two digits on 400 are zeros so 5 and 7 stay the same. with 857, you must now subtract 2 because you added 2 earlier. 857 - 2 = 855.

4 0
3 years ago
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