Answer:
D. nothing, as the alkyne would not react to an appreciable extent.
Explanation:
Nothing, as the alkyne would not react to an appreciable extent.
Answer:
31 bits.
Explanation:
Given, total number of registers = 55
Total instructions = 60
Size of memory = 16 KB
Now, no of registers are 55. We find the next greater or equal power of 2 which is 64 = 26. Hence, 6 bits are required to represent a register operand.
Number of instructions = 60. We find the next greater or equal power of 2 which is 64 = 26. Hence, 6 bits are required to represent a instruction.
Size of memory = 64 KB = 26 * 210 * 23 bits = 219 bits. Hence, 19 bits are required to represent a memory location.
Now, an instruction has 2 parts, opcode and operand. As given there are only two address instructions which are memory operand and register operand.
Hence, total bits would be: 6 bits (opcode) + 6 bits (register operand) + 19 (memory operand) = 31 bits.
Your answer would be 5098 liters.
Reason being, because there are 1,000,000 liters in one megalitre, so you just multiply 0.005098 by 1,000,000 to get your answer of 5098 liters.
Answer:
See explaination for the illustrations on the question.
Explanation:
A program cache miss usually occurs at the instance of an instruction fetch failing to read an instruction from the program cache and the processor is required to access the instruction from the next level of memory. A request to L2 or external memory has a much higher latency than an access from the first level instruction cache.
A cache on its own can be defined as is a hardware cache used by the central processing unit (CPU) of a computer to reduce the average cost (time or energy) to access data from the main memory.
Please kindly check attachment for the step by step diagramming illustrations of the questions.
I think that the answer wiloukd be B. For #31 and for #32 A.