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Usimov [2.4K]
3 years ago
7

Kendra remembered glue. ally remembered an eraser

Mathematics
1 answer:
statuscvo [17]3 years ago
8 0

sarah remembered scissors

please be more specific

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Use multiplication or division of power series to find the first three nonzero terms in the Maclaurin series for the function. (
Mrrafil [7]

Answer:

So, the first three nonzero terms in the Maclaurin series are:

6, \, 27x^2, \, \frac{405x^4}{4}.

Step-by-step explanation:

From exercise we have the next function y = 6 sec(3x).

We know that Maclaurin series for the function sec x, have the following form:

\sec x=1+\frac{x^2}{2}+\frac{5x^4}{24}+...

So, for the given function y = 6 sec(3x), we get:

y = 6 \sec(3x)=6+27x^2+\frac{405x^4}{4}+...

So, the first three nonzero terms in the Maclaurin series are:

6, \, 27x^2, \, \frac{405x^4}{4}.

6 0
3 years ago
Consider the following.
saul85 [17]

Answer:

Step-by-step explanation:

jack is correct

3 0
3 years ago
A rectangular Persian carpet has a perimeter of 172 inches. The length of the carpet is 26 inches more than the widthWhat are th
quester [9]
Hope this helps :)
So the carpets length is 56in. And the width is 30in.

6 0
3 years ago
The slope of the graphed line is 2. Which formulas 3 represent the line that is graphed? Check all that apply. y-1 = (x - 2) 3 O
yuradex [85]

Answer:

never ever learned this but maybe The answer is:

b. y - 2 = 2/3(x-1)

c. y - 4 = 2/3(x-4)

e. f(x) = 2/3 + 4/3

Step-by-step explanation:

bce

3 0
3 years ago
The map of a walking trail is drawn on a coordinate grid with three points of interest. The trail starts at R(−2, 4) and goes to
Bogdan [553]
Length from R(-2, 4) to S(3, 4) is sqrt((3 - (-2))^2 + (4 - 4)^2) = sqrt(5)^2 = 5 units

Length from S(3, 4) to T(3, -1) is sqrt((3 - 3)^2 + (-1 - 4)^2) = sqrt(-5)^2 = 5 units

Therefore, total length = 5 + 5 = 10 units.
5 0
3 years ago
Read 2 more answers
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