Answer:
f(x) = x^3 + x^2 - 33x + 63
Step-by-step explanation:
The zeros are x = 3, x = 3, x = -7.
A polynomial function with zeros x1, x2, x3, ..., xn has the form:
f(x) = (x - x1)(x - x2)(x - x3) ... (x - xn)
The zeros of this function are 3, 3, -7.
The function is:
f(x) = (x - 3)(x - 3)(x - (-7))
f(x) = (x - 3)(x - 3)(x + 7)
Now we multiply out the right side.
f(x) = (x^2 - 6x + 9)(x + 7)
f(x) = x^3 + 7x^2 - 6x^2 - 42x + 9x + 63
f(x) = x^3 + x^2 - 33x + 63
