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vovikov84 [41]
3 years ago
10

What is the area of the isosceles trapezoid shown?

Mathematics
2 answers:
igor_vitrenko [27]3 years ago
8 0

Answer:

the answer is 80

Step-by-step explanation:

you can split the trapezoid into a rectangle and two triangles to find the area

balandron [24]3 years ago
4 0

If you want the area of the entire trapeziod.

The formula for area of a trapeziod is:

1/2h(b₁+b₂)

So the equation applied to the trapeziod is:

2.5(20+12)

20+12 is 32. 32 multiplied by  2.5 is 80.

<h3><u><em>Your answer is 80.</em></u></h3>
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Which expression is equivalent to the given expression?
I am Lyosha [343]

Answer:

C. - 4x^2 + 5x - 4

Step-by-step explanation:

just expand the equation and you'll get C

6 0
3 years ago
Read 2 more answers
I NEED HELP WITH ME MATH
ruslelena [56]

ok so lets start of with the fact that the whole thing is 21 units.

So we do 21-9=12 so then we now know that the rectangle is 12 so then we do 12*8 units which is= 96 . Now the triangles. so the first one we know that its 8*3 and times it by 1/2 because two triangles is equal to a rectangle so the first triangle is 12 and now the second. its 9-3= 6 then its 6*8*1/2 which is equal to 24 so now the final answer is

96+12+24 which is equal to 132 so i'm guessing it 132 square units

5 0
3 years ago
Xyz^(2) if x=2 y=7 and z=-4
Afina-wow [57]

Answer:

-224

Step-by-step explanation:

xyz^2

(2)(7)(-4)^2

14 x -16

-224

8 0
2 years ago
Using the Segment Addition Postulate, find the value of m.
Naya [18.7K]

Answer:

36

Step-by-step explanation:

AB + BC = AC

4m - 15 + 5m - 6 = 15

m - 21 = 15

m = 36

4 0
3 years ago
Rectangle ABCD has vertices at (-7,-2); (1, -2); (1, -8); and (-7, -8) respectively. If GHJK is a similar rectangle where G(2, 5
Minchanka [31]

Answer:

J (6,2) K (2,2)

Step-by-step explanation:

Now distance of AB = [(y2-y1)^2 + (x2-x1)^2]^(1/2)

                                = 8 units

CB =  [(y2-y1)^2 + (x2-x1)^2]^(1/2)

= 6 units by using same formula

Now AB/CB must equal to GH/HJ as rectangles are similar

GH =  [(y2-y1)^2 + (x2-x1)^2]^(1/2)

= 4 units

so

8/6 = 4/HJ

So,

HJ = 3 units

Now if we see the coordinates given carefully, it is obvious that two perpendicular lines lie perfectly parallel to x and y coordinates in rectangle ABCD.  A is (-7,-2) and B is (1,-2) which means distance along y-axis doesn't change. Similarly for C (1,-8) and D (-7,-8), one can see that distance between y-axis doesn't change. So lines AB and CD of rectangle are parallel with x and AD and BC are parallel with y-axis.

In rectangle GHJK one can see that in given coordinates, G(2,5) and H(6,5), y coordinate is same so it is parallel to x axis. Now, HJ is perpendicular to GH so it must be parallel to y axis. It means if we know the lengths of sides we can easily determine unknown coordinates by simple addition and subtraction.

So,  we know HJ = 3 units

J is (6,2) since HJ is parallel to y axis so distance on x axis will remain unchanged and length of line HJ will effect distance of y axis.

Similarly K is (2,2) for the same reason.

6 0
3 years ago
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