Area=1/2 times base times height
given
base=11in
height=6in
area=1/2 times 11 times 6
area=66/2 square inches
area=33 square inches
the area is 33 in²
2l + 2w = 16
2(l+ w) = 16 Divide both sides by 2
l + w = 16/2
l + w = 8
So for example the length l could be 5 and the width could be 3.
Length could be 5.
Answer:
It has 3 sides and the measure is 3
Step-by-step explanation:
If A and B are equal:
Matrix A must be a diagonal matrix: FALSE.
We only know that A and B are equal, so they can both be non-diagonal matrices. Here's a counterexample:
![A=B=\left[\begin{array}{cc}1&2\\4&5\\7&8\end{array}\right]](https://tex.z-dn.net/?f=A%3DB%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%262%5C%5C4%265%5C%5C7%268%5Cend%7Barray%7D%5Cright%5D)
Both matrices must be square: FALSE.
We only know that A and B are equal, so they can both be non-square matrices. The previous counterexample still works
Both matrices must be the same size: TRUE
If A and B are equal, they are literally the same matrix. So, in particular, they also share the size.
For any value of i, j; aij = bij: TRUE
Assuming that there was a small typo in the question, this is also true: two matrices are equal if the correspondent entries are the same.