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Alexeev081 [22]
3 years ago
14

A video sharing website starts with 20,000 members. Each year it loses 25% of the members, but adds 10,000 new members after the

reduction. Write a recursive rule to find the number of members for any year.
Mathematics
1 answer:
Paraphin [41]3 years ago
4 0
Hello there!

So, as we see here, we can see that they start out with 20,000 members. 25% of 20,000 would be 5,000 members.

So, every year, they lose 25% which is 5,000 members of they team. But then they gain 10,000 more.

So, practically, they get 5,000 every year even though they get 25% off.

5,000 would be the answer.
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8. The trapezoids are similar. The area of the smaller trapezoid is 131 m2. Find the area of the larger trapezoid to the nearest
kolbaska11 [484]

Answer:

3,726\ m^{2}

Step-by-step explanation:

step 1

Find the scale factor

we know that

If two figures are similar, then the ratio of its corresponding sides is equal to the scale factor

Let

z----> the scale factor

x----> corresponding side of the larger trapezoid

y----> corresponding side of the smaller trapezoid

z=\frac{x}{y}

we have

x=64\ m

y=12\ m

substitute

z=\frac{64}{12}

step 2

Find the area of the larger trapezoid

we know that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

Let

z----> the scale factor

x----> area of the larger trapezoid

y----> area of the smaller trapezoid

z^{2}=\frac{x}{y}

we have

z=\frac{64}{12}

y=131\ m^{2}

substitute

(\frac{64}{12})^{2}=\frac{x}{131}

x=(\frac{4,096}{144})(131)

x=3,726\ m^{2}

5 0
3 years ago
PLEASE HELP ME !! WILL GIVE BRAINLIEST!!
PolarNik [594]
B is a times b
C is  also a times b

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6 0
3 years ago
Solve the following simultaneous linear equations by the substitution method.
anyanavicka [17]

Answer:

p = 2 and q = 2

Step-by-step explanation:

hope this helps please like and mark as brainliest

5 0
3 years ago
Approximately 5% of calculators coming out of the production lines have a defect. Fifty calculators are randomly selected from t
baherus [9]

Answer:

0.2611 = 26.11% probability that exactly 2 calculators are defective.

Step-by-step explanation:

For each calculator, there are only two possible outcomes. Either it is defective, or it is not. The probability of a calculator being defective is independent of any other calculator, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

5% of calculators coming out of the production lines have a defect.

This means that p = 0.05

Fifty calculators are randomly selected from the production line and tested for defects.

This means that n = 50

What is the probability that exactly 2 calculators are defective?

This is P(X = 2). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{50,2}.(0.05)^{2}.(0.95)^{48} = 0.2611

0.2611 = 26.11% probability that exactly 2 calculators are defective.

3 0
3 years ago
Find the length and width of a rectangle that has the given area and a minimum perimeter. Area: 162 square feet
Gnom [1K]

Answer:

The width and length of rectangle is 12.728 m

Step-by-step explanation:

Let the length of the rectangle = L

let the width of the rectangle = W

The subjective function is given by;

F(p) = 2(L + W)

F = 2L + 2W

Area of the rectangle is given by;

A = LW

LW = 162 ft²

L = 162 / W

Substitute in the value of L into subjective function;

f = 2l + 2w\\\\f = 2(\frac{162}{w} )+2w\\\\f = \frac{324}{w} + 2w\\\\\frac{df}{dw} = \frac{-324}{w^2} +2\\\\

Take the second derivative of the function, to check if it will given a minimum perimeter

\frac{d^2f}{dw^2}= \frac{648}{w^3} \\\\Thus, \frac{d^2f}{dw^2}>0, \ since,\frac{648}{w^3} >0 \ (minimum \ function \ verified)

Determine the critical points of the first derivative;

df/dw = 0

\frac{-324}{w^2} +2 = 0\\\\-324 + 2w^2=0\\\\2w^2 = 324\\\\w^2 = \frac{324}{2} \\\\w^2 = 162\\\\w= \sqrt{162}\\\\w = 12.728 \ m

L = 162 / 12.728

L = 12.728 m

Therefore, the width and length of rectangle is 12.728 m

3 0
3 years ago
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