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3 years ago

Best answer gets BRAINLIEST and 30 pts

Mathematics

2 answers:

a_sh-v [17]3 years ago

6 0

X=chicken

Y=steak

X+Y=6

14x+17y=99

Ainat [17]3 years ago

5 0

Answer:

One person ordered chicken, and five people ordered steak.

X=Chicken

Y=Steak

Step-by-step explanation:

X+Y=6

14x + 17y= 99

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The equation y=x is a function. True or False?

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Answer:

false

Step-by-step explanation:

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4 years ago

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a square flower garden in Samantha's backyard has an area of 100 square feet how much fencing will she need to enclose the flowe

Arlecino [84]

If Samantha's backyard has an area of 100 square feet, and you need to know how much fencing to enclose the garden, you know you are looking for the parameter of the garden. To fine the parameter you have to know the length of the sides. Area of a square is length times width and length and width are the same value. So what you know the square-root of 100 is the value of each side. So each side of the garden is 10 feet long. To find parameter all you do is add up all four sides. 10+10+10+10 = 40 feet need to enclose the flower garden.<span />

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4 years ago

A closed, rectangular-faced box with a square base is to be constructed using only 36 m2 of material. What should the height h a

kkurt [141]

Answer:

$b=h=\sqrt{6}$ m

Step-by-step explanation:

Let

Bas length of box=b

Height of box=h

Material used in constructing of box=36 square m

We have to find the height h and base length b of the box to maximize the volume of box.

Surface area of box= $2b^2+4bh$

$2b^2+4bh=36$

$b^2+2bh=18$

$2bh=18-b^2$

$h=\frac{18-b^2}{2b}$

Volume of box, V= $b^2h$

Substitute the values

$V=b^2\times \frac{18-b^2}{2b}$

$V=\frac{1}{2}(18b-b^3)$

Differentiate w. r.t b

$\frac{dV}{db}=\frac{1}{2}(18-3b^2)$

$\frac{dV}{db}=0$

$\frac{1}{2}(18-3b^2)=0$

$\implies 18-3b^2=0$

$\implies 3b^2=18$

$b^2=6$

$b=\pm \sqrt{6}$

$b=\sqrt{6}$

The negative value of b is not possible because length cannot be negative.

Again differentiate w.r.t b

$\frac{d^2V}{db^2}=-3b$

At $b=\sqrt{6}$

$\frac{d^2V}{db^2}=-3\sqrt{6}$

Hence, the volume of box is maximum at $b=\sqrt{6}$ .

$h=\frac{18-(\sqrt{6})^2}{2\sqrt{6}}$

$h=\frac{18-6}{2\sqrt{6}}$

$h=\frac{12}{2\sqrt{6}}$

$h=\sqrt{6}$

$b=h=\sqrt{6}$ m

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3 years ago

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