Lim ln([(x+1)/x]^3x) as x ->.infinity =lim ln([(x+1)^(3x)]/[x^(3x)]) as s->infinity =lim ln((x+1)^(3x))-ln(x^(3x)) = infinity - infinity
your answer is e3 but you can use l'hopital if you liketake the log, get 3xln(1+1/x)which is in the form ∞×0 then use the usual trick of rewriting as ln(1+1/x)/1/3x
The value of x is B. 70°.
The angles of a triangle always add up to 180°. First, you must subtract 40 from 180 to know the sum of the remaining angles.
180 - 40 = 140 ⇒ The sum of the remaining angles is 140°
The Isosceles triangle theorem states that if two sides of a triangle are congruent, then the angles opposite those sides are congruent. Since the angle measurements of the remaining two angles are congruent, to find the value of x, you have to divide the sum of the remaining angles by 2.
140/02 = 70 ⇒ The value of x is 70°
385 + 326 + 298 = 1,009 / 3 = 336.33
385 + 326 + 298 + x = 350
350 x 4 = 1,400
1,400 - 1,009 = 391
385 + 326 + 298 + 391 = 1,400 / 4 = 350
The answer is $391
I would divide 12 by 10 and after doing that, I would get 1.2. Hope this helps!