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4 years ago

Which two numbers of the given data set have the same absolute value? Explain your answer in full sentences.

Mathematics

2 answers:

bezimeni [28]4 years ago

6 0

Answer:

The answer is -5 and 5 because when you do absolute value if there is a negative number then it turns into a positive number. Negatives will always turn out as positives when doing absolute value. :)

Step-by-step explanation:

const2013 [10]4 years ago

3 0

Answer: the two numbers that have the same absolute value is -5, and 5.

Step-by-step explanation:

Absolute will just make any negatives to positive.

So, the absolute value of -5 is 5, or the absolute value of -3, is 3.

If it's already positive, then nothing happens; it stays the same

So, the absolute value of 8 is 8, nothing is changed.

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Ahat [919]

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3 years ago

How is 7/6 the same as 21/18 please how do i show my work

Oduvanchick [21]

Answer:

Multiply 7/6 by 3/3

Step-by-step explanation:

Multiplying 7/6 by 3/3 will give you a result of 21/18.

Hope this helps!

6 0

4 years ago

Read 2 more answers

Operations with complex numbers <br>I+6i

IRISSAK [1]

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4 years ago

Drag each volume of a prism to match a rectangular prism

Hunter-Best [27]

The volume of the rectangular prism with the dimensions given are as follows:

v = 72 inches³

v = 36 inches³

v = 80 inches³

v = 54 inches³

<h3>Volume of a rectangular prism</h3>

v = lwh

where

l = length

w = width

h = height

Therefore,

v = 4 × 3 × 6 = 72 inches³

v = 6 × 3 × 2 = 36 inches³

v = 4 × 5 × 4 = 80 inches³

v = 2 × 9 × 3 = 54 inches³

learn more on rectangular prism here: brainly.com/question/13512346

4 0

2 years ago

Solve 5x^2 - 7x + 2 = 0 by completing the square.

Reika [66]

Answer: The correct option is (c) $\dfrac{49}{100}.$

Step-by-step explanation: We are given to solve the following quadratic equation by the method of completing the square:

$5x^2-7x+2=0~~~~~~~~~~~~~~~~~~~(i)$

Also, we are to find the constant added on both sides to form the perfect square trinomial.

We have from equation (i) that

$5x^2-7x+2=0\\\\\Rightarrow x^2-\dfrac{7}{5}x+\dfrac{2}{5}=0\\\\\\\Rightarrow x^2-2\times x\times \dfrac{7}{10}+\left(\dfrac{7}{10}\right)^2+\dfrac{2}{5}=\left(\dfrac{7}{10}\right)^2\\\\\\\Rightarrow \left(x-\dfrac{7}{10}\right)^2=\dfrac{49}{100}-\dfrac{2}{5}\\\\\\\Rightarrow \left(x-\dfrac{7}{10}\right)^2=\dfrac{49-40}{100}\\\\\\\Rightarrow \left(x-\dfrac{7}{10}\right)^2=\dfrac{9}{100}\\\\\\\Rightarrow x-\dfrac{7}{10}=\pm\dfrac{3}{10}\\\\\\\Rightarrow x=\pm\dfrac{3}{10}+\dfrac{7}{10}.$

So,

$x=\dfrac{3}{10}+\dfrac{7}{10},~~~~~~~~x=-\dfrac{3}{10}+\dfrac{7}{10}\\\\\\\Rightarrow x=\dfrac{10}{10},~~~~~~~~\Rightarrow x=\dfrac{-3+7}{10}\\\\\\\Rightarrow x=1,~-\dfrac{2}{5}.$

Thus, the required solution is $x=1,~-\dfrac{2}{5}.$ and the value of the constant added is $\dfrac{49}{100}.$

Option (c) is correct.

3 0

3 years ago