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Charra [1.4K]
3 years ago
5

Work out the balance for £4500 invested for 2 years at 4% per annum

Mathematics
1 answer:
AnnZ [28]3 years ago
4 0

This situation can be represented by a geometric sequence, where each term is the balance each successive year:

U_{n} = a * r^{n}

Un = the balance on the nth year

a = intial balance

r = multiplier

n = number of years

From the information:

a = 4500

r = 1.04

(4% increase per annum is the equivalent of multiplying by 1.04 so the multiplier is 1.04)

n = 2

So:

U_{2} = 4500 * (1.04)^{2} \\= 4867.2

The balanc after two years is: £4867.20

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Answer:

90 engines must be made to minimize the unit cost.

Step-by-step explanation:

Vertex of a quadratic function:

Suppose we have a quadratic function in the following format:

f(x) = ax^{2} + bx + c

It's vertex is the point (x_{v}, y_{v})

In which

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How many engines must be made to minimize the unit cost?

x value of the vertex. So

x_{v} = -\frac{b}{2a} = -\frac{-180}{2(1)} = 90

90 engines must be made to minimize the unit cost.

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