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3 years ago

11

What is the sum of the first 30 terms in a(n)=4n+1

1 answer:

dimulka [17.4K]3 years ago

6 0

Hello,

$\sum _{i=1} ^{30}(a_i)=\sum _{i=1} ^{30}(4*i+1)\\

=4*\sum _{i=1} ^{30}(i) +\sum _{i=1} ^{30}(1)\\

=4* \dfrac{31*30}{2} + 30 =1860+30=1890$

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