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Brrunno [24]
3 years ago
10

Find the average value of f(x) = 1/x over the interval [e, 2e].

Mathematics
1 answer:
pogonyaev3 years ago
8 0
\bf \displaystyle \cfrac{1}{2e-e}\int_{e}^{2e}~\cfrac{1}{x}\cdot dx\implies \left. \cfrac{1}{e}\cdot ln(x) \right]_{e}^{2e}\implies \left[ \cfrac{ln(2e)}{e} \right]-\left[  \cfrac{ln(e)}{e}\right]
\\\\\\
\left[ \cfrac{ln(2)+ln(e)}{2e}  \right]-\left[ \cfrac{1}{e} \right]\implies \cfrac{ln(2)}{e}+\cfrac{ln(e)}{e}-\cfrac{1}{e}\implies \cfrac{ln(2)}{e}+\cfrac{1}{e}-\cfrac{1}{e}
\\\\\\
\cfrac{ln(2)}{e}
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