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Keith_Richards [23]
3 years ago
12

How many more people attended the magics game than attended the pacers game. Help :(

Mathematics
2 answers:
nirvana33 [79]3 years ago
8 0
Indiana pacers = 582.295
orlando magic = 715.901

715.901 - 582.295 = <span>133.606

therefore </span><span>133.606 more people attended the magics than pacers 
</span> 
(it was quite blurry so sorry if the numbers are incorrect..)


Sophie [7]3 years ago
8 0

Answer:

Number of more people = 133,606

Step-by-step explanation:

The number of people attended Magics game are: 715,901

The number of people attended Pacers game are: 582,295

⇒ The Number of more people attended the magics game than attended the pacers game = Number of people attended Magics game - Number of people attended Pacers game

⇒ Number of more people = 715,901 - 582,295 = 133,606

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andreyandreev [35.5K]
5(n-4)=(4n-12)

First: Distribute 5 into n and -4.
5(n-4)=(5n)+(5*-4)= 5n-20.

Second: Subtract 4n from both sides to eliminate the variable from the right side of the equation.

(5n-20)=(4n-12)

n-20=-12

Next: Add 20 to both sides to eliminate the constant from the left side of the equation.

n-20=-12

n=8

The unknown number is 8.
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3 years ago
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Trapezoid ABCD is graphed in a coordinate plane.
Ann [662]

Answer:

12

Step-by-step explanation:

he coordinates of the vertices of the trapezoid ABCD are:

A=(-5,-2)=(xa,ya)→xa=-5, ya=-2

B=(-1,2)=(xb,yb)→xb=-1, yb=2

C=(0,-1)=(xc,yc)→xc=0, yc=-1

D=(-2,-3)=(xd,yd)→xd=-2, yd=-3

yi x(i+1)        xi     yi     xi y(i+1)

                 -5    -2

(-2)(-1)=2     -1      2     (-5)(2)=-10

(2)(0)=0       0     -1     (-1)(-1)=1

(-1)(-2)=2    -2    -3     (0)(-3)=0

(-3)(-5)=15   -5    -2     (-2)(-2)=4

S1=-10+1+0+4→S1=-5

S2=2+0+2+15→S2=19

Area: A=(1/2) Absolute value (S1-S2)

A=(1/2) Absolute value (-5-19)

A=(1/2) Absolute value (-24)

A=(1/2) (24)

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3 years ago
The probability that a single radar station will detect an enemy plane is 0.65.
taurus [48]

Answer:

a) We need 4 stations to be 98% certain that an enemy plane flying over will be detected by at least one station.

b) If seven stations are in use, the expected number of stations that will detect an enemy plane is 4.55.

Step-by-step explanation:

For each station, there are two two possible outcomes. Either they detected the enemy plane, or they do not. This means that we can solve this problem using concepts of the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

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The probability that a single radar station will detect an enemy plane is 0.65. This means that n = 0.65.

(a) How many such stations are required to be 98% certain that an enemy plane flying over will be detected by at least one station?

This is the value of n for which P(X = 0) \leq 0.02.

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P(X = 0) = C_{1,0}.(0.65)^{0}.(0.35)^{1} = 0.35

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P(X = 0) = C_{2,0}.(0.65)^{0}.(0.35)^{2} = 0.1225

n = 3

P(X = 0) = C_{3,0}.(0.65)^{0}.(0.35)^{3} = 0.0429

n = 4

P(X = 0) = C_{4,0}.(0.65)^{0}.(0.35)^{4} = 0.015

We need 4 stations to be 98% certain that an enemy plane flying over will be detected by at least one station.

(b) If seven stations are in use, what is the expected number of stations that will detect an enemy plane?

The expected number of sucesses of a binomial variable is given by:

E(x) = np

So when n = 7

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If seven stations are in use, the expected number of stations that will detect an enemy plane is 4.55.

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