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ladessa [460]
3 years ago
9

jill traveled to the ferry office and back. the trip there took 5 hours and the trip back took 4 hours. she averaged 65 mph on t

he return trip. find the average speed of the trip there
Mathematics
1 answer:
antoniya [11.8K]3 years ago
4 0

We know from physics class that the formula for distance of a linear motion is given as:

d = v t

Where,

d = distance travelled

v = average velocity

t = time it took to reach the destination

Since the distance going to the office and back is just similar, therefore we can simply equate the two:

v1 t1 = v2 t2

Where 1 signifies going to the office and 2 signifies going back from the office. Therefore this yields to:

v1 * 5 hours = 65 mph * 4 hours

v1 = 52 mph

 

<span>Answer: The average speed going to the office is 52 mph.</span>

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Step-by-step explanation:

3/5 ---> ?/100

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5       20         100

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2 + 0.6

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<h2>Hope this helps!!</h2>
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Lady_Fox [76]

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\text{The slope-intercept form of an equation of a line:}\\y=mx+b\\m-slope\\b-y\ intercept

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