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ladessa [460]
3 years ago
9

jill traveled to the ferry office and back. the trip there took 5 hours and the trip back took 4 hours. she averaged 65 mph on t

he return trip. find the average speed of the trip there
Mathematics
1 answer:
antoniya [11.8K]3 years ago
4 0

We know from physics class that the formula for distance of a linear motion is given as:

d = v t

Where,

d = distance travelled

v = average velocity

t = time it took to reach the destination

Since the distance going to the office and back is just similar, therefore we can simply equate the two:

v1 t1 = v2 t2

Where 1 signifies going to the office and 2 signifies going back from the office. Therefore this yields to:

v1 * 5 hours = 65 mph * 4 hours

v1 = 52 mph

 

<span>Answer: The average speed going to the office is 52 mph.</span>

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Solve A=p+prt for r.
Furkat [3]

A = p + prt

The above equation can be solved for “r” in such a way.

Subtract “p” from both sides;

A – p = p + prt – p

A – p = prt

Divide both sides by “p” and “t”;

A/pt – p/pt = prt/pt

A/pt – 1/t = r

Or

<span>r =  A/pt – 1/t</span>

3 0
3 years ago
15 POINTS!
joja [24]
8x + (2x - 14)= 7x + 3x -14

10x -14= 10x - 14

These equations are identical, so it would be the  identity property and the answer would either be identity or the fancy 'R'.
6 0
3 years ago
2. En la ciudad de Quito, en la temporada fría, se registran temperaturas que van desde los 5 °C hasta los 18 °C. En la temporad
natulia [17]

Answer:

(See explanation below for further detail/Véase la explicación abajo para mayores detalles)

Step-by-step explanation:

(This exercise is written in Spanish and explanations will be held in such language)

a) Las temperaturas quedan representadas a continuación:

Quito - Temporada Fría

Intervalo

5 ^{\circ}C \leq t \leq 18^{\circ}C (Este intervalo indica si el dato puede pertenecer a la temporada fría)

Conjunto

C = \{\forall t \in \mathbb {R}| 5 \leq t \leq 18\} (Este conjunto acumula todo el registro de las temperaturas de la temporada fría)

Quito - Temporada Cálida

Intervalo

4 ^{\circ}C \leq t \leq 30^{\circ}C (Este intervalo indica si el dato puede pertenecer a la temporada cálida)

Conjunto

H = \{\forall t \in \mathbb {R}| 4 \leq t \leq 30\} (Este conjunto acumula todo el registro de las temperaturas de la temporada cálida)

b) La temperatura de la ciudad de Quito pertenece esencialmente a dos intervalos:

Intervalo de Temporada Fría:

5 ^{\circ}C \leq t \leq 18^{\circ}C

Intervalo de Temporada Cálida:

4 ^{\circ}C \leq t \leq 30^{\circ}C

c) Toda temperatura mayor o igual que 4 °C y menor o igual que 30 °C.

d) Temperaturas mayores o iguales a 5 °C y menores o iguales a 18 °C.

e) Temperaturas mayores o iguales a 4 °C y menores o iguales a 30 °C.

6 0
3 years ago
Determine the critical value for a 98% confidence interval when the sample size is 12 for the t ‑distribution. Enter the positiv
Natalija [7]

Answer:

+2.718

Step-by-step explanation:

from the question,

the sample size is 12

therefore the degree of freedom,

df = 12 - 1

= 11

alpha = 1 - 0.98

= 0.02

this is because the confidence level is 98%

under the t distribution table, a degree of freedom of 11 and 0.02 alpha level = <em>2.718</em>

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<em>I </em><em>hop</em><em>e</em><em> </em><em>th</em><em>is</em><em> </em><em>helps</em><em>!</em>

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Help please i need it asap
Levart [38]
The correct answer would be 6
8 0
3 years ago
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