Question

In Mr. Navarro’s first period class, 17/28 of the students got an A on their math test. In his second period class, 11/28 of the students got an A. What fraction more of the students got an A in Mr. Navarro’s first period class? Write in simplest form.

Answer 1

his first period class got 6/28 more students that got As than his 2nd period

Answer 2

Answer:

$\frac{6}{28}$ more students got an A.

Simplest form of the fraction will be $\frac{3}{14}$

Step-by-step explanation:

In the first period of Mr Navarro's class, fraction of students  got an A = $\frac{17}{28}$

In second period class, number of students who got an A = $\frac{11}{28}$

Now we have to calculate the fraction of more students who got an A in Mr Navarro's first period class = $\frac{17}{28}-\frac{11}{28}$

                                                    = $\frac{17-11}{28}$

                                                    = $\frac{6}{28}$

Therefore, $\frac{6}{28}$ more students got an A in Mr Navarro's first period class.

To change this fraction in the simplest form we will divide the numerator and denominator by 2.

$\frac{6}{28}=\frac{3}{14}$