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4 years ago

PLEASE HELP ME WITH THIS

Mathematics

2 answers:

krok68 [10]4 years ago

8 0

Answer:

Step-by-step explanation:

So we have the equation:

$y=\sqrt{x-3}$

This is a square root equation.

For square root equations, the radicand(s) <em>must</em> be positive.

Therefore, to find the domain, set the radicand to be greater than or equal to 0:

$x-3\geq 0$

Solve for x. Add 3 to both sides:

$x\geq 3$

Therefore, our domain <em>must</em> be greater than or equal to 3.

In set notation, this is:

$\{x:x\geq 3\}$

Therefore, our answer is C.

solong [7]4 years ago

8 0

All we need to do is solve for the 0 of the function.

Solution:

0 = √x-3

0^2 = x - 3

0 = x - 3

3 = x

The domain is greater than or equal to 3 and this can be written as x ≥ 3 or in other words, Option 3.

Best of Luck!

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1 year ago

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