The temperature was 80f and then fell 20f

PLZ I NEED HELP NOW THANKS

xeze [42]

Answer:

1240.4 mm²

Step-by-step explanation:

SA of Pentagonal pyramid:

(as)(5/2) + (sl)(5/2)

↑ ↑

base area lateral area

_____________________

a: apothem (in-radius) length, s: side length.

l: slant height.

______________________

Since we are already given the base area which is 440.4 mm². All we need to do is find the lateral area and add both areas together.

Given that the triangular face of the lateral part has a side/base length of 16mm, and a 20mm slant height.

A triangle has an area of ½bh and since there are 5 of these faces total, (5)(½bh) = (5/2)(bh). In a three dimensional perspective, b will be s and h will be l so (sl)(5/2).

With this information the surface area is:

(16)(20)(5/2)mm + (440.4 mm²) →

800 mm² + 440.4 mm² =

1240.4 mm²

7 0

3 years ago

Find all solutions for 2y - 4x =2 y = 2x + 1 site:socratic.org

sladkih [1.3K]

Answer:

All real numbers would be the solution

Step-by-step explanation:

2y - 4x =2 and y = 2x + 1

We solve but placing the value of y into the first equation:

2(2x + 1) - 4x = 2

Next we distribute the 2 through the parenthesis:

4x + 2 - 4x = 2

Now we gather like terms:

2 = 2 ( note the 4x and - 4x cancel out)

Since 2 =2 this tells us that all real numbers would work.

5 0

3 years ago

describe the relationship between the lengths of the sides and the measures of the angles in a triangle.

Kitty [74]

What is another way to write the equation <span>?

</span>

8 0

4 years ago

Read 2 more answers

A closed box with a square base is to have a volume of 171 comma 500 cm cubed. The material for the top and bottom of the box co

Zepler [3.9K]

Answer:

$C(x)=\dfrac{20x^3+1715000}{x}\\$Minimum cost, C(35)=\$29,400$

The dimensions that will lead to minimum cost of the box are a base length of 35 cm and a height of 140 cm.

Step-by-step explanation:

Volume of the Square-Based box=171,500 cubic cm

Let the length of a side of the base=x cm

Volume $=x^2h$

$x^2h=171,500\\h=\dfrac{171500}{x^2}$

The material for the top and bottom of the box costs $10.00 per square centimeter.

Surface Area of the Top and Bottom $=2x^2$

Therefore, Cost of the Top and Bottom $=\$10X2x^2=20x^2$

The material for the sides costs $2.50 per square centimeter.

Surface Area of the Sides=4xh

Cost of the sides=$2.50 X 4xh =10xh

$\text{Substitute h}$=\dfrac{171500}{x^2} $into 10xh\\Cost of the sides=10x(\dfrac{171500}{x^2})=\dfrac{1715000}{x}$

Therefore, total Cost of the box

$= 20x^2+\dfrac{1715000}{x}\\C(x)=\dfrac{20x^3+1715000}{x}$

To find the minimum total cost, we solve for the critical points of C(x). This is obtained by equating its derivative to zero and solving for x.

$C'(x)=\dfrac{40x^3-1715000}{x^2}\\\dfrac{40x^3-1715000}{x^2}=0\\40x^3-1715000=0\\40x^3=1715000\\x^3=1715000\div 40\\x^3=42875\\x=\sqrt[3]{42875}=35$

Recall that:

$h=\dfrac{171500}{x^2}\\Therefore:\\h=\dfrac{171500}{35^2}=140cm$

The dimensions that will lead to minimum costs are base length of 35cm and height of 140cm.

Therefore, the minimum total cost, at x=35cm

$C(35)=\dfrac{20(35)^3+1715000}{35}=\$29,400$

8 0

3 years ago

Solve:

s2008m [1.1K]

I hope this helps you

y+z=4-x

5x+4-x=16

4x=12

x=3

x+y+z+x-y+4z=4+27

2x+5z=31

2.3+5z=31

5z=25

z=5

x+y+z=4

3+y+5=4

y=-4

8 0

4 years ago